Question

Help

Answer 1

(2x^-4)(3x^2)

Answer 2

\[(2x^{-4})*(3x^{2})\]

Answer 3

Right

Answer 4

ok let's re-write this first

Answer 5

hello Phonton

Answer 6

do you see that negative exponent on 2x^-4 ?

\[x^{-n} = \frac{ 1 }{ x^{n} }\]

Answer 7

Yes

Answer 8

hi @AceSpeedFighter

Answer 9

U saying 2/4

Answer 10

\[2x^{-4} = \frac{ 1 }{ 2x^{4} }\]

Answer 11

Oh. Ok. I see that.

Answer 12

okay unrelated but can you re-write

\[x^{-7} \] for me?

Answer 13

I would say 1/x^7

Answer 14

yes good

Answer 15

Thanks

Answer 16

\[2x^{-4}=\frac{ 2 }{ x^4 }\]

Answer 17

Well you can multiply by 2x^4, right?

Answer 18

no oops lol it's 2/x^-4

Answer 19

\[\frac{ 2 }{ x^{4} }*(3x^{2})\]

Answer 20

ok. I see that so far. This is the hardest part foe me

Answer 21

can you say 6x^2 / x^4

or 6x^2 ^-4

Answer 22

okay you're on the right track

Answer 23

6 is correct but there's another rule

Answer 24

\[\frac{ x^{2} }{ x^{4} } \]

here's another rule

\[\frac{ x^{a} }{ x^{b} } = x^{a-b}\]

Answer 25

Oh ok. hum

Answer 26

see the 2 and the 4 those exponents

Answer 27

based on the rule what would you have to do?

Answer 28

So is it 6 x^2 -x^4

Answer 29

or 6^-x2

Answer 30

\[\frac{ 6x^{2} }{ x^{4} } = 6(x^{2-4}) = 6x^{-2} \rightarrow \frac{ 6 }{ x^{2} }\]

Answer 31

ok. I got it now. Thanks.

Answer 32

whenever you divide two numbers that have the same base in this case x is our base, then you subtract the exponents and keep the base

Answer 33

It has been so long I forgot but yea I do remember that subtraction rule now!

Answer 34

for example in division \[\frac{ x^{4} }{ x^{2} } = x^{4-2} = x^2\] notice both of the bases or x so we can subtract them if they weren't the same we couldn't carry out the operation.

Answer 35

What would you do if unlike bases?

Answer 36

\[\frac{ x^{4} }{ y^{2} }\] we would just leave this as it is or we could say

\[x^{4}•y^{-2}\]

Answer 37

Thanks so much for that review!

Answer 38

np