Please help! I'll fan and medal Find an equation for the nth term of the sequence. -3, -12, -48, -192, ... an = 4 • -3n + 1 an = -3 • 4n - 1 an = -3 • 4n an = 4 • -3n
@freckles
@mathmate @yanasidlinskiy
Please help
.=multiplication?
ask yourself these questions: what pattern do you notice? is this a geometric or arithmetic sequence? is there a common ratio or a common difference? what can i do to get from a previous term to the term after?
Can you help me solve it?
I think you have not written your choices correctly
That's how they were
so there were no exponents in the choices?
Yes all of the "n" on the end of each choice is an exponent
ok well if you didn't know how to answer any of the questions i presented above ... then try this: plug in 1 into all of your choices and see which one spots out the first term in your sequence (the -3)
How? I'm not good at these
how to replace n with 1 and evaluate?
wherever there is an n, you put 1
then see if you get the result a1=-3 from it
for example: you should see two n's here \[a_n=-4 \cdot 3^{n+1}\]
replace the n's with 1
Ohhhh okay
I got -3 as the first number am I right?
So it would either be B or C right?
which of those two choices given you -3 when you replace n with 1
B
sounds good you can remember it like this you have a common ratio that means you can always do term divided by previous term and get the same number that is you can do (term)/(previous term)=same number so you can always just plug your numbers into \[a_n=\text{ first term} \cdot (\text{common ratio number} )^{n-1}\]
Wow thank you so much so to clarify, I am correct with choice B?
that nth term right there only works for geometric sequences
"sounds good"<-----
well that is if you meant choice B to be a_n=-3 \cdot 4^{n-1}
Can you help with just one more? I can open a new question
\[a_n=-3 \cdot 4^{n-1}\]
Yes thank you so much
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