A punter kicks a football upward with an initial speed of 48 feet per second. After how many seconds does the ball hit the ground?
Use the formula h = rt − 16t2 where h represents height in feet and r represents the initial speed.
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OpenStudy (afloridagirl):
is it three?
OpenStudy (afloridagirl):
@agent0smith
OpenStudy (welshfella):
when ball hits the ground h = 0
OpenStudy (afloridagirl):
so 0?
OpenStudy (welshfella):
solve
0 = 48t - 16t^2
t will be one root - corresponding to when the ball was kicked
Its the other root you want.
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OpenStudy (afloridagirl):
oh
OpenStudy (welshfella):
factoring
t(48 - 16t) = 0
OpenStudy (welshfella):
so t = 0 and 48 - 16t = 0
OpenStudy (afloridagirl):
so its 0?
OpenStudy (welshfella):
solve the second equation and you have the answer
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OpenStudy (afloridagirl):
3?
OpenStudy (welshfella):
No - you want value of t when ball hits the ground after trvalling through the air
OpenStudy (welshfella):
48 - 16t = 0
16t = 48
t = 3 yea
OpenStudy (afloridagirl):
so wait is it or isnt it three?
OpenStudy (afloridagirl):
im sorry im hella confused at this moment
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OpenStudy (welshfella):
yes it is 3
the solution to 48-16t = 0 is t = 3
OpenStudy (afloridagirl):
okay thank you
OpenStudy (welshfella):
t = 0 seconds corresponds to when the ball is kicked and after 3 seconds it lands on ground again.
OpenStudy (welshfella):
- in both cases h = 0.
OpenStudy (afloridagirl):
so wait whats the answer?
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OpenStudy (welshfella):
the question asks for the time taken to reach the ground after being kicked.