Question

Geometry Questions!
Can anyone help me with questions 6-10? Thank you! Any help at all is appreciated.

https://static.k12.com/eli/bb/343/4_23944/1_124721_4_23948/b2f8bba5d2851b765bae9d114d0313fbe149d221/media/ff5c925ed3a1a89077a667749c0f7fdf07768770/SpecialRightTriangles_WritingAssignment.pdf

Answer 1

Question 6
Find the height of the large triangle
sine 45 = height/hypotenuse
height = sine 45 * 8
height = 0.70711 * 8
height = 5.65688

The triangle on the right is a 30 - 60 - 90 triangle with the side opposite the 30 degree angle = to the height 5.65688
The hypotenuse (side x) is twice this length = 5.65688 *2= 11.31376

The triangle base (side y) = ([sq root (3)] / 2) * hypotenuse =
0.866025 * 11.31376 = 9.797999004
http://www.1728.org/trig2.htm

Answer 2

@wolf1728 Thank you!

Answer 3

hi ! i like help you but please collaborate - ok. ?

Answer 4

courage please

Answer 5

so exercise 6. is ok. yes ? what about 7 . ?

Answer 6

so these two lines inside rectangle are bisectors - yes ? so what mean these ,how many degrees has an angle halfed of a rectangle - do you know it ?

Answer 7

cosine of this angle will be equal by x/3sqrt2 and from this you can calculi easy the value of x

Answer 8

@jhonyy9 Hi! Sorry, I was busy. Yes, I see where you're going.

Answer 9

hi ! ok : do oyu can answering my question ?

Answer 10

do you - sorry

Answer 11

how many degrees has a halfed angle of a rectangle how is in this your exercise case ?

Answer 12

I'm sorry @jhonyy9 , but what do you mean by that?

Answer 13

Question 8
Once again this page http://www.1728.org/trig2.htm
is a big help
If you have a 45 45 90 triangle, each of the sides is equal to the hypotenuse * 1/sq root (2)
or each of the legs = hypotenuse * 0.7071067812
So we have hypotenuse = 15 inches
legs of the triangle = 15 * 0.7071067812 = 10.606601718 inches

Answer 14

Question 9
The altitude of the equilateral triangle is 36 feet.
The altitude of the triangle divides the triangle into 2 30-60-90 triangles
Heck, let's go to that page http://www.1728.org/trig2.htm once again
So the medium side of the 30-60-90 triangle equals 36 feet.
The hypotenuse of a 30-60-90 triangle equals the ("medium side" * 2/(sq root of 3))
hypotenuse = 36 * 1.1547005384
hypotenuse = 41.5692193824

Answer 15

@wolf1728 Thanks so much! Do you know how to solve 10 and 7? I've input the 3's into the calculator, but I'm confused as to why it is that number since when I tried to solve it by hand I got a completely different answer.

Answer 16

Heck, guess I'll do question 10
Here's a page to help you http://www.1728.org/trig2.htm
The triangle on the left is a 30-60-90 triangle
The middle size (which is 12) when multiplied by 2/sq root(3) = the hypotenuse

hypotenuse (or side z) = 12* 1.1547005384
= 13.8564064608
side y = (1/2) side z = 6.9282032304

Side x is part of a 45-45-90 triangle.
side x = 12 * (1/sq root(2)
side x = 8.4852813742

Answer 17

Question 7
That "middle triangle" is a 45-45-90 triangle.
Side y = 3* sq root (2) * (sq root (2))
[Remember sqrt(2) * sqrt(2) = 2]
Side y = 3 * 2
Side y = 6

Side x is the leg of a 45-45-90 triangle.
The hypotenuse = sq root(3) * 2
leg = hypotenuse * (1/sq root(1/sq root (2))
leg = 3 * sq root(2) * (1/sq root (2))
The sq root of2 cancels out and your answer is
the leg or side x = 3

Answer 18

@wolf1728 Oh, okay, I get it! I mixed up the formulas for the 45-90-45 and the 30-90-60 triangles. Thanks!

Answer 19

u r welcome :-)