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Mathematics 24 Online
OpenStudy (yumyum247):

math halp plz!!!

OpenStudy (yumyum247):

http://prntscr.com/bs6rxg

OpenStudy (yumyum247):

Something is telling me i did this all wrong!!! :"(

OpenStudy (yumyum247):

@sshayer

OpenStudy (yumyum247):

@jim_thompson5910

OpenStudy (yumyum247):

i don't thing my average rate of change should be this high

jimthompson5910 (jim_thompson5910):

When it asks for "average rate of change" it usually gives you a starting point and an ending point. But it only gave you one point, the twelfth month. Are you sure it doesn't ask "what is the average rate of change over the 12 months?" ie, from t = 0 to t = 12?

OpenStudy (yumyum247):

wait let me post the snap shot of the original thing

OpenStudy (yumyum247):

http://prntscr.com/bs6w14

OpenStudy (yumyum247):

did it halp?!?!?!?!

jimthompson5910 (jim_thompson5910):

so it sounds like they want you to find the average rate of change from month t = 11 to t = 13? or maybe from t = 12 to t = 13? or maybe from t = 11 to t = 12? it's not exactly clear what they want for part (a)

OpenStudy (yumyum247):

yeah i think it's from 11th to 12th month..

jimthompson5910 (jim_thompson5910):

and as for your equation, I would use \[\Large P = A*(2)^t\] where P = population after t months A = initial population (in this case 14) t = time in months

jimthompson5910 (jim_thompson5910):

`yeah i think it's from 11th to 12th month..` ok compute \[\Large \frac{P(12)-P(11)}{12-11}\] using the function \[\Large P(t) = 14*(2)^t\]

OpenStudy (yumyum247):

|dw:1468371401952:dw|

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