Parallelogram FGHJ was dilated and translated to form similar parallelogram F'G'H'J'.
What is the scale factor of the dilation?
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OpenStudy (samirahdanyel):
OpenStudy (thecatman):
how many times does the original fit in the other
OpenStudy (samirahdanyel):
how are you suppose to find that out
OpenStudy (thecatman):
translate figures into squares
OpenStudy (thecatman):
2x2 and 16x16
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OpenStudy (samirahdanyel):
4 and 256
OpenStudy (thecatman):
sorry 8x8
OpenStudy (samirahdanyel):
thats 64
OpenStudy (thecatman):
its 1/8 th
OpenStudy (thecatman):
sorry i meant 8 i had it backwards
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OpenStudy (samirahdanyel):
so its just 8?
OpenStudy (thecatman):
thats what i found but you might need a better source
OpenStudy (samirahdanyel):
@jim_thompson5910 what you think?
OpenStudy (thecatman):
@DullJackel09 we need an opinion
jimthompson5910 (jim_thompson5910):
FG is 2 units long. Count the number of squares going from F to G
F'G' is 8 units long. Again, count the squares to determine this
Divide the segments
(length of F'G')/(length of FG) = 8/2 = 4
so the scale factor is actually 4
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jimthompson5910 (jim_thompson5910):
length of F'G' = 4*(length of FG)
so each corresponding side of F'G'H'J' is 4 times as long as FGHJ