Question Below.
I have about 12 practice questions. Here is # 1. \[\sin(45-\theta)=\sqrt{2/2}\](____) cos θ+sin θ cos θ-sin θ sin θ- cos θ sin θ-cos θ
I do not even know where to begin in completing the problem.
do you know for what angle \(\sf\Large sin ~\theta = \frac{\sqrt{2}}{2}\)
And I have no clue what those last four lines are... answer choices? o.O
I do not.
well... umm.. use the unit circle? https://www.mathsisfun.com/geometry/images/circle-unit-304560.gif The x-coordinate is the cos value for the angle, and the y-coordinate is the sin value for the angle
yes they are answer choices.
In that case, I have no clue what your question is really asking. If it was asking for what theta was, then I can understand but otherwise no clue
maybe which answer choice makes it an identity?
oh, I see now this is what we have to use: sin(A − B) = sin A cos B − cos A sin B and hint: sin45 = sqrt(2)/2 and cos45 = sqrt(2)/2
so what do we substitute? Do I use sqrt(2)/2? Sorry I just started this course yesterday.
we start with the left hand side. Plug in 45 for A and \(\theta\) for B and open it up :)
so then we get \[\sqrt{2\cos \theta}/2 - \sin(\theta)\sqrt{2}/2\]
oops but the cos theta is not under the sqrt
yes, now we factor out the sqrt(2)/2 from it Example: ab + ac = a( b + c) this is the distributive formula, but we're using it backwards kind of :P
so do we still use the 45 for a and theta for b?
yes, we currently have: \(\Large sin(45 - \theta) = \frac{\sqrt{2}}{2}cos\theta - sin\theta \frac{\sqrt{2}}{2}\) All we have to do is factor \(\Large\frac{\sqrt{2}}{2}\) from the right hand side. :)
oh okay
so I got \[\theta=\pi/4+\pi*\]
I dont think I fully understand what to do sorry
we aren't solving for theta :) if you factor out the sqrt(2)/2 you'll get your final answer also a side note, we were given 45 degrees. That means the answer should be kept in degrees (if we were solving for theta)
but none of the answer choices are in degrees
what does that mean
if we were solving for theta, then the answer would have to be degrees since we were given degrees. Here we aren't solving for theta. We're trying to simplify what sin(45 - theta) is
so what do I have to do to factor correctly?
ab + ac becomes a(b + c) \(\Large sin(45 - \theta) = \frac{\sqrt{2}}{2}cos\theta -\frac{\sqrt{2}}{2}sin \theta\) All we have to do is factor \(\Large\frac{\sqrt{2}}{2}\) from the right hand side. :)
so then it becomes cos theta - sin theta right/?
Correct! And that's your answer :D
aw haha thanks a bunch youre super !!
Anytime! :)
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