Ask your own question, for FREE!
Mathematics 11 Online
OpenStudy (diamondanon2):

Question Below.

OpenStudy (diamondanon2):

I have about 12 practice questions. Here is # 1. \[\sin(45-\theta)=\sqrt{2/2}\](____) cos θ+sin θ cos θ-sin θ sin θ- cos θ sin θ-cos θ

OpenStudy (diamondanon2):

I do not even know where to begin in completing the problem.

TheSmartOne (thesmartone):

do you know for what angle \(\sf\Large sin ~\theta = \frac{\sqrt{2}}{2}\)

TheSmartOne (thesmartone):

And I have no clue what those last four lines are... answer choices? o.O

OpenStudy (diamondanon2):

I do not.

TheSmartOne (thesmartone):

well... umm.. use the unit circle? https://www.mathsisfun.com/geometry/images/circle-unit-304560.gif The x-coordinate is the cos value for the angle, and the y-coordinate is the sin value for the angle

OpenStudy (diamondanon2):

yes they are answer choices.

OpenStudy (diamondanon2):

TheSmartOne (thesmartone):

In that case, I have no clue what your question is really asking. If it was asking for what theta was, then I can understand but otherwise no clue

OpenStudy (diamondanon2):

maybe which answer choice makes it an identity?

TheSmartOne (thesmartone):

oh, I see now this is what we have to use: sin(A − B) = sin A cos B − cos A sin B and hint: sin45 = sqrt(2)/2 and cos45 = sqrt(2)/2

OpenStudy (diamondanon2):

so what do we substitute? Do I use sqrt(2)/2? Sorry I just started this course yesterday.

TheSmartOne (thesmartone):

we start with the left hand side. Plug in 45 for A and \(\theta\) for B and open it up :)

OpenStudy (diamondanon2):

so then we get \[\sqrt{2\cos \theta}/2 - \sin(\theta)\sqrt{2}/2\]

OpenStudy (diamondanon2):

oops but the cos theta is not under the sqrt

TheSmartOne (thesmartone):

yes, now we factor out the sqrt(2)/2 from it Example: ab + ac = a( b + c) this is the distributive formula, but we're using it backwards kind of :P

OpenStudy (diamondanon2):

so do we still use the 45 for a and theta for b?

TheSmartOne (thesmartone):

yes, we currently have: \(\Large sin(45 - \theta) = \frac{\sqrt{2}}{2}cos\theta - sin\theta \frac{\sqrt{2}}{2}\) All we have to do is factor \(\Large\frac{\sqrt{2}}{2}\) from the right hand side. :)

OpenStudy (diamondanon2):

oh okay

OpenStudy (diamondanon2):

so I got \[\theta=\pi/4+\pi*\]

OpenStudy (diamondanon2):

I dont think I fully understand what to do sorry

TheSmartOne (thesmartone):

we aren't solving for theta :) if you factor out the sqrt(2)/2 you'll get your final answer also a side note, we were given 45 degrees. That means the answer should be kept in degrees (if we were solving for theta)

OpenStudy (diamondanon2):

but none of the answer choices are in degrees

OpenStudy (diamondanon2):

what does that mean

TheSmartOne (thesmartone):

if we were solving for theta, then the answer would have to be degrees since we were given degrees. Here we aren't solving for theta. We're trying to simplify what sin(45 - theta) is

OpenStudy (diamondanon2):

so what do I have to do to factor correctly?

TheSmartOne (thesmartone):

ab + ac becomes a(b + c) \(\Large sin(45 - \theta) = \frac{\sqrt{2}}{2}cos\theta -\frac{\sqrt{2}}{2}sin \theta\) All we have to do is factor \(\Large\frac{\sqrt{2}}{2}\) from the right hand side. :)

OpenStudy (diamondanon2):

so then it becomes cos theta - sin theta right/?

TheSmartOne (thesmartone):

Correct! And that's your answer :D

OpenStudy (diamondanon2):

aw haha thanks a bunch youre super !!

TheSmartOne (thesmartone):

Anytime! :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!