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Find solutions of system of equalities that satisfy y > z System: x + y + z = 12 x + yz = 19
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Hints: 1. Solve for the limiting case where y=z, i.e. solve the system x+y+y=12; x+y*y = 19 The solution consists of two values of y={y1,y2}, which are the two limiting values. I.e. either \(y1\le y \le y2\) , or, \((-\infty,y] \cup [y\le +\infty)\) Check the domain that is valid, and call this D(y). 2. Solve original system for x and z in terms of y, i.e. x(y), and z(y). The solution is therefore x(y), and z(y) with y \(\in\) D(y).
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