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Engineering 7 Online
OpenStudy (raffle_snaffle):

strengths

OpenStudy (raffle_snaffle):

OpenStudy (raffle_snaffle):

OpenStudy (mathmate):

A couple of things, note: all measurements are in kips, inches except M which is in kip-ft. 1. Area-moment of inertia, I For parts 3 and 4, the depth should be (d-t)=4.3-0.32=3.98 2. I have x_bar=1.836 3. I have I=19.968, for some reason your I is way larger. I use for each part I=Area(height^2/12+(x_bar-cg)^2) Also, for parts 1,2 and 5, I use the full width a & b, so that parts 3 and 4 have their cg at exactly d/2. 4. Moments equal -4.5 kip-ft=54 kip-in. You have correctly calculated compression at the bottom flange because M=-4.5 kip-ft. Some of my intermediate values: Total area = 6.8864 in^2 \(\sum\)Area*x = 12.64064 x_bar = 1.83559 I=19.9676 Sb=I/x_bar=10.8780 (bottom) St=I/(d-x_bar)=8.1024 M=-54 kip-in I'll let you figure out \(\sigma_{top}\) and \(\sigma_{bottom}\).

OpenStudy (raffle_snaffle):

I got it right. max t = 2548psi = 2.54 ksi max c = -1894 psi = -1.89 ksi

OpenStudy (mathmate):

Excellent!

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