Question

How do I solve x-6y<_12
(<_ means less than or greater to)
~Graphing Inequalities~

Answer 1

what do u think it is

Answer 2

I'm not sure, that's why I asked :c

Answer 3

@TheSmartOne

Answer 4

x-6y <= 12 so this mean less or equal 12
than you need graphing this inequality so write it hence

6y >= x-12

y >= (x-12)/6

so for x = 0 get y = (-12)/6 = - 2

for x=12 will get y=0



hope this helped

Answer 5

@TheSmartOne opinion please - ty

Answer 6

you could change the relation (as if it were an equation) except *no divide or multiply by a negative number*

\[ x-6y\le12 \]
solving for y:
add 6 y to both sides
\[ x \le 6y +12\]
add -12 to both sides
\[ x -12 \le 6y\]
divide both sides by 6
\[ \frac{1}{6}x -2 \le y \\
y \ge \frac{1}{6}x -2\]

Answer 7

you could plot this as the line
\[ y = \frac{1}{6}x -2 \]
and then, because it is really
\[ y \ge \frac{1}{6}x -2 \]
"shade in" the region above the line where y is "above" or bigger than the line

Answer 8

How do I solve x-6y<_12
(<_ means less than or greater to)
~Graphing Inequalities~

First, your slope intercept form: y = mx + b where m is the slope and m is the y-intercept.
Try to put the equation x - 6y <= 12 in that form.
Remember you switch the signs when multiplying/dividing by a negative number. So you have y => -2 + x/6 or y => x/6 -2. Now we have to graph that. Well, it's fairly simple now. 1/6 is your slope since mx = x/6 and if you divide x from that: x/6 * 1/x the x's cancel eachother out and you're left with 1/6. So this is the equation so far: y => 1/6 + b. And your b is just -2. So y => 1/6 - 2. Graph that. Need more help?