There are 4 blue pencils, 2 red pencils, and 3 orange pencils. What is the probability of choosing an orange pencil then a blue pencil without replacement?

A) 2/36

B) 3/12

C) 10/72

D) 12/72

Question

There are 4 blue pencils, 2 red pencils, and 3 orange pencils. What is the probability of choosing an orange pencil then a blue pencil without replacement?
	
A)   	2/36
	
B)   	3/12
	
C)   	10/72
	
D)   	12/72

yolo_king · Answer

I just need help finding these kinds of answers.

yolo_king · Answer

I think its  $$3/9 *4/6$$

yolo_king · Answer

12/18 = 6/9 = 2/3

yolo_king · Answer

thats all i got...

sweetburger · Answer

Ok so your first number is 3/9. How did you get 4/6 for your second number?

yolo_king · Answer

four blues and it said without replacment so theres six left

yolo_king · Answer

since i cant replace the oranges

sweetburger · Answer

but you only removed one pencil so how did you go from 9 total pencils to 6?

yolo_king · Answer

ooooooooooo i removed one not three my bad so it should be 4/8

sweetburger · Answer

yea

yolo_king · Answer

So D?

calculusxy · Answer

$\frac{1}{3} \times \frac{1}{2} = \frac{1}{6}$ which is equivalent to \(\frac{12}{72}\. So you're correct.

calculusxy · Answer

$\frac{12}{72}$

yolo_king · Answer

I got a couple more if you guys dont mind

yolo_king · Answer

Thanks a lot btw

undeadknight26 · Answer

I knew the answer was 12/72 I was just confused on how I got there and after I got there once I couldn't get there again it was depressing.