The non-profit organization you volunteer for is throwing a fundraiser cookout. You are in charge of buying the hamburgers, which cost $3 per pound, and hot dogs, which cost $2 per pound. The meat budget you are given totals $600 dollars. The inequality 3x + 2y less than or equal to 600 represents the possible combinations of pounds of hamburgers (x) and hot dogs (y) you can buy.

http://prntscr.com/btbex0

Question

The non-profit organization you volunteer for is throwing a fundraiser cookout. You are in charge of buying the hamburgers, which cost $3 per pound, and hot dogs, which cost $2 per pound. The meat budget you are given totals $600 dollars. The inequality 3x + 2y less than or equal to 600 represents the possible combinations of pounds of hamburgers (x) and hot dogs (y) you can buy.

http://prntscr.com/btbex0

oswaldmurphy · Answer

Which of the following represents a solution to the inequality?

 200 pounds of hamburgers and 140 pounds of hot dogs
 150 pounds of hamburgers and 60 pounds of hot dogs
 100 pounds of hamburgers and 240 pounds of hot dogs
 240 pounds of hamburgers and 40 pounds of hot dogs

oswaldmurphy · Answer

@agent0smith @Ciarán95 @Jadeishere

blank · Answer

do you want to know how its done in which case you can just plug in the answer choices to see which one would work

oswaldmurphy · Answer

What would the answer be? B? Or C?

ciarán95 · Answer

$$3x + 2y \le 600$$

For each option given, plug in the values for x and y, work out the left-hand side and see if the inequaity holds (i.e. if it is less than or equal to 600).

oswaldmurphy · Answer

Ok.

oswaldmurphy · Answer

So it is B. Thanks :D

ciarán95 · Answer

No worries @OswaldMurphy ! So, for example, with Option B:

x = 150, y = 60

$$3(150) + 2(60) \le 600$$
$$450 + 120\le600$$
$$570 \le 600$$

which is true, so the inequality holds here and B is correct.