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Find the exact area of the surface obtained by rotating the curve about the x-axis. 9x = y^2 + 27, 3 ≤ x ≤ 7
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Should I get y in terms of x first?
I would not bother. notice we can write this as x= (1/9) y^2 + 3 3 <= x < 7 which is a ( shaped parabola if you like you could switch all the x and y's: y = (1/9) x^2 + 3 3 <= y <= 7 (corresponding to x=0 to 6) rotated about the y-axis
using y = (1/9) x^2 + 3 3 <= y <= 7 I get \[SA = 2\pi \int\limits_{0}^{6}(\frac{ 1 }{ 9 }x^2+3)\sqrt{\frac{ 4 }{ 81 }x^2 +1} dx\]
is this correct?
using the "switched x-y version"
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