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Mathematics 16 Online
OpenStudy (glorylove):

How would I go about simplifying this equation?

OpenStudy (glorylove):

\[\frac{ 2 }{ x ^{2} - x } - \frac{ 1 }{ x }\]

OpenStudy (glorylove):

I know I have to factor/find a common denominator, but I'm having difficulty.

zepdrix (zepdrix):

The denominators actually have a common factor. It's difficult to see it at first though. Let's factor this expression to start, \(\large\rm x^2-x\) Each term shares something in common, see it? :)

OpenStudy (glorylove):

The x's, right?

zepdrix (zepdrix):

Mmm good, they both have an x. If we pull that out of each term,\[\large\rm x(x-1)\]

zepdrix (zepdrix):

Any confusion on that first factoring step? :o\[\large\rm \frac{2}{x(x-1)}-\frac{1}{x}\] After that, you'll notice that they share the x denominator, ya?

OpenStudy (glorylove):

No confusion there, I can follow that easily enough. :) And yes, I see they share the x-denominator.

zepdrix (zepdrix):

So I guess we have to give our second fraction this (x-1) in order to get a common denominator. Giving to both the numerator and denominator.\[\large\rm \frac{2}{x(x-1)}-\frac{1}{x}\cdot\color{royalblue}{\frac{(x-1)}{(x-1)}}\]

OpenStudy (glorylove):

Ohh, okay! That makes sense. So from there I just combine the rational expressions and simplify, right?

zepdrix (zepdrix):

Good, yes. You can combine it into a single fraction,\[\large\rm \frac{2-1(x-1)}{x(x-1)}\]and simplify.

OpenStudy (glorylove):

\[\frac{ x -1 }{ x(x - 1) }\] , right? Or am I missing something?

OpenStudy (glorylove):

Okay, that definitely can't be right. Out of four options I'm given, this isn't one of them.

zepdrix (zepdrix):

Woops, make sure you distribute the subtraction to each term in the brackets.

OpenStudy (glorylove):

Whoops, okay! Thank you so much for your help!

zepdrix (zepdrix):

Figure it out? :) np

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