Question

expand the squared binominal (x+4)^2

Answer 1

a. x^2-16
b. x^2+16
c. x^2+8x+16
d. x^2-8x+16

Answer 2

c.?

Answer 3

yep

Answer 4

state the degree of the polynomial xy+3x^2 -7+x

Answer 5

a.1
b.2
c.3
d.4

Answer 6

The degree of any polynomial is the "x" with the highest exponent which in this case is 3x^2 so the degree is 2.

Answer 7

simplify - (a^2-4a-6)-(-a^2-7a-6)

Answer 8

2a^2+3a
2a^2+3a-12
2a^2-11a
2a^2+11a

Answer 9

I dont think the answer choices match the problem

Answer 10

its one of them

Answer 11

well i got 11a+12

Answer 12

@AaronAndyson @sweetburger

Answer 13

@Jadeishere

Answer 14

(a^2-4a-6)-(-a^2-7a-6)
a^2 - (-a^2) = 2a^2
-4a - (-7a) = -3a
-6 - (-6) = 0

2a ^2 - 3a

When subtracting polynomial expressions, only subtract the like terms. So a^2, a and no coefficient, in this case :)

Answer 15

OH, oops! -4a - (-7a) = 3a, sorry
It would actually be
2a^2 + 3a

Answer 16

oh I thought the "-" sign in front of the first polynomial was part of the expression so i multiplied that into the polynomial

Answer 17

I almost did that, actually.. xD Great job helping him with the other questions. Next time, really, REALLY try to explain the answers a little more in depth :) It helps people even more! Good luck @KingOGCobraXx and thanks @Blank for helping out!

Answer 18

thank you for the tip!

Answer 19

@Blank ? can you answer my question

Answer 20

Since this question asks you to add two polynomials, there is no distributing the minus sign so its a lot easier than a subtraction problem. All you have to do is add the like terms in the two polynomials, so \[2x^2 + 3x^2 = 5x^2\], and \[-11x +11x = 0\], so you get 5x^2-4

Answer 21

(3x^2 - 6x + 7) - (x^2 - 6x + 4)
3x^2 - 6x +7 - x^2 + 6x - 4
3x^2 - x^2 - 6x + 6x + 7 - 4
2x^2 + 3

It's the same as before, distribute the minus sign and add/subtract like terms. I'm sure you understand how to do it by now. You should do some on your own for practice now

Answer 22

i could do it myself but it would take awhile i have alot of work today and iv taken hours on this test

Answer 23

\[-3x^2y^2 * x^4\]
Since your multiplying it by x^4 multiply only the x terms so x^2 and x^4. When you are multiplying numbers or variables with exponents you keep the bottom number/variable and add the exponent so you will get x^6. the new expression will be \[-3x^6y^2\]

Answer 24

You basically do the same thing. First multiply the x^2 s in the second expression to get \[3x^4y\]. Leave the z as it is because it does not have another like term and multiply all the other numbers/variables. You then get \[18x^5y^4z\]

Answer 25

In an expression like that, you multiply the outer exponent outside the parentheses by the exponents inside the parentheses. This one is a simple one, so I would like you to do this one.

Answer 26

a or b id say b tho

Answer 27

yep its b

Answer 28

This one is another simple one. All you have to do is distribute the outside term to each of the inside terms, so that means multiplying 10x to every term inside the parentheses.
so it will look like \[(10x)9x^2 + (10x)6x + (10x)7\] So the answer will be \[90x^3 + 60x^2 +70x\]

Answer 29

I have to go eat now. Sorry i cant help you any further than this.

Answer 30

6 more questions @karim728 ? please

Answer 31

sorry i really cant right now

Answer 32

@CandyCove

Answer 33

@YumYum247