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Mathematics 13 Online
OpenStudy (jonathan5824):

Fan and medal So if i have 15 squared + 8 squared = hypotenuse squared what is the hypotenuse

OpenStudy (mrjackdzi):

17

OpenStudy (jonathan5824):

how do you get that

OpenStudy (mrjackdzi):

15*15 is 225 and 225 + 64 is 284

OpenStudy (mrjackdzi):

oh whoops 9

OpenStudy (jonathan5824):

here is the original triangle

OpenStudy (mrjackdzi):

its a number either ending in 9

jimthompson5910 (jim_thompson5910):

`15 squared` or `15^2` means we multiply 15 by itself twice 15^2 = 15*15 = 225

jimthompson5910 (jim_thompson5910):

think of a square with side length 15 |dw:1468889795900:dw|

OpenStudy (jonathan5824):

yes i understand that i just dot understand how you got 9

OpenStudy (mrjackdzi):

and 7^2 and 3^3 end in 9

OpenStudy (mrjackdzi):

oh

jimthompson5910 (jim_thompson5910):

the area of this square is base*height = 15*15 = 225 |dw:1468889818248:dw|

OpenStudy (mrjackdzi):

just add 15*15 and 8*8

OpenStudy (mrjackdzi):

you get 289

OpenStudy (jonathan5824):

yeah how do you get 9 from that

OpenStudy (mrjackdzi):

the last number

jimthompson5910 (jim_thompson5910):

@mrjackdzi originally wrote 284 but corrected to mean 289 he just changed the last digit

OpenStudy (mrjackdzi):

yes

jimthompson5910 (jim_thompson5910):

225+64 = 289

OpenStudy (jonathan5824):

so the answer is 9

OpenStudy (mrjackdzi):

so the only numbers that you square that end in nine is 3 and 7

OpenStudy (mrjackdzi):

the answer is not nine, it is a number who ends in 3 or 7

OpenStudy (mrjackdzi):

maybe jim can explain

jimthompson5910 (jim_thompson5910):

15^2 = 225 8^2 = 64 so 15^2+8^2 = 225+64 = 289 the 289 is equal to the hypotenuse squared. We want the hypotenuse without the square so if x = length of hypotenuse then x^2 = 289 x = ??? hint: apply the square root to both sides

OpenStudy (mrjackdzi):

i just did guess and check with 13 and 17

OpenStudy (mrjackdzi):

@jim_thompson5910 's strategy is easier to understand though

OpenStudy (mrjackdzi):

good job

OpenStudy (jonathan5824):

Ok thanks i checked all of my equation and it all works out can you help with one more question please

OpenStudy (mrjackdzi):

ok

OpenStudy (jonathan5824):

The moon forms a right triangle with the Earth and the Sun during one of its phases, as shown below: A right angle triangle is shown with the Earth at the right angle. The acute angle between the line joining the Earth and the Sun and the Sun and the moon is x degrees. The distance between the Earth and the Sun is y. A scientist measures the angle x and the distance y between the Earth and the Sun. Using complete sentences, explain how the scientist can use only these two measurements to calculate the distance between the moon and the Sun.

OpenStudy (mrjackdzi):

oh i remember this

OpenStudy (jonathan5824):

|dw:1468890169853:dw|

OpenStudy (mrjackdzi):

call the distance opposite from x z

OpenStudy (jonathan5824):

ok

OpenStudy (mrjackdzi):

so what trigonometric function can you use for this?

OpenStudy (jonathan5824):

you would use sin correct

OpenStudy (mrjackdzi):

you don't know the hypotnotuse so you can't use it

jimthompson5910 (jim_thompson5910):

yes the hypotenuse is unknown, but it still factors into the problem

OpenStudy (jonathan5824):

so then we must use tan

OpenStudy (mrjackdzi):

yes you could use it

OpenStudy (mrjackdzi):

and tan would work yes

OpenStudy (jonathan5824):

ok

jimthompson5910 (jim_thompson5910):

`Using complete sentences, explain how the scientist can use only these two measurements to calculate the distance between the moon and the Sun.` |dw:1468890649650:dw|

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