The reaction time for an automobile driver is 0.7s. If the automobile decelarated at 5m/s^2 calculate the total distance travelled by the automobile in coming to rest from an initial velocity of 8.33 m/s after a signal is observed.
bc isme kya problem h ?
bc kyu prob nahi h bas method verify karna tha
work dikha apna?
v^2 = u^2 + 2aS 0 = (8.33)^2 + 2aS -69.38 = 10S S = -6.938 magnitude taking we get S = 6.938m now, t = 0.7 s = 8.33 d = st = 0.7*8.33 = 5.831, D = d+S=6.938+5.831 = 12.77=12.8m
a=-5 hoga na
deccelarate kr raha h
oops...baki sab sahi h na?
d=8.33 kaise ho gaya?
tera toh yeh aaya tha na magnitude taking we get S = 6.938m
s*t karna 8.33*0.7 is 5.831
arrey! s=6.938 tha na
abe S = 6.938 tha m s VELOCITY chaman
theek se padhna bhai tu muhje dara deta h
lol S se kyun donate krta h v se krna
lol mujhe confuse kr diya
donate? do u mean DENOTE? XD
lol yea
ha tuh d = vt = 8.33*0.7 = 5.831
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