The reaction time for an automobile driver is 0.7s.
If the automobile decelarated at 5m/s^2 calculate the total distance travelled by the automobile in coming to rest from an initial velocity of 8.33 m/s after a signal is observed.
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OpenStudy (mayankdevnani):
bc isme kya problem h ?
OpenStudy (aaronandyson):
bc kyu prob nahi h bas method verify karna tha
OpenStudy (mayankdevnani):
work dikha apna?
OpenStudy (aaronandyson):
v^2 = u^2 + 2aS
0 = (8.33)^2 + 2aS
-69.38 = 10S
S = -6.938
magnitude taking we get S = 6.938m
now,
t = 0.7
s = 8.33
d = st = 0.7*8.33 = 5.831,
D = d+S=6.938+5.831 = 12.77=12.8m
OpenStudy (mayankdevnani):
a=-5
hoga na
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OpenStudy (mayankdevnani):
deccelarate kr raha h
OpenStudy (aaronandyson):
oops...baki sab sahi h na?
OpenStudy (mayankdevnani):
d=8.33 kaise ho gaya?
OpenStudy (mayankdevnani):
tera toh yeh aaya tha na
magnitude taking we get S = 6.938m
OpenStudy (aaronandyson):
s*t karna
8.33*0.7 is 5.831
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OpenStudy (mayankdevnani):
arrey! s=6.938 tha na
OpenStudy (aaronandyson):
abe S = 6.938 tha m s VELOCITY chaman
OpenStudy (aaronandyson):
theek se padhna bhai
tu muhje dara deta h
OpenStudy (mayankdevnani):
lol S se kyun donate krta h
v se krna
OpenStudy (mayankdevnani):
lol mujhe confuse kr diya
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