Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
that's the approx length of PR. Make sure to round it to two decimal places
OpenStudy (volleyballlover55):
ok so thats it? this is the complete answer?
The approximate length of PR:
a^2+b^2 = c^2
9^2 + 14^2 = x^2
81+196=x^2
277=x^2
x^2=277
sqrt (x^2)=sqrt(277)
x=16.6433
OpenStudy (volleyballlover55):
whats 16.6433 rounded to two decimal places? 16.64?
OpenStudy (volleyballlover55):
well it says to round it to the nearest hundredth..
jimthompson5910 (jim_thompson5910):
`whats 16.6433 rounded to two decimal places? 16.64?`
correct
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
`well it says to round it to the nearest hundredth..`
yes that's the same as saying "round to 2 decimal places"
OpenStudy (volleyballlover55):
ok!!! so is this the final answer?
The approximate length of PR:
a^2+b^2 = c^2
9^2 + 14^2 = x^2
81+196=x^2
277=x^2
x^2=277
sqrt (x^2)=sqrt(277)
x=16.6433
16.6433 rounded to the nearest hundredth is 16.64.
jimthompson5910 (jim_thompson5910):
that just takes care of part A
jimthompson5910 (jim_thompson5910):
make sure you include the name of the theorem you used
OpenStudy (volleyballlover55):
oh really? we arent done?
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (volleyballlover55):
ohhhh!!! lol we arent done.. i didnt see there was a part b! whoopsies!
OpenStudy (volleyballlover55):
did we use the pythagorean theorem for part a?
jimthompson5910 (jim_thompson5910):
`did we use the pythagorean theorem for part a?`
yes
OpenStudy (volleyballlover55):
ok!
now lets move on to part b!
jimthompson5910 (jim_thompson5910):
PR is now 18 ft
PQ stays at 14 ft
the question they want us to find out: how long is QR?
|dw:1469069287385:dw|
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
I want you to try to set up the equation
OpenStudy (volleyballlover55):
ok so the first two steps are???
jimthompson5910 (jim_thompson5910):
what's the longest side here?
OpenStudy (volleyballlover55):
a^2+b^2 = c^2
18^2+14^2=c^2
is that correct so i can start solving?
jimthompson5910 (jim_thompson5910):
no, keep in mind that c is the longest side
c = 18 is the longest side
a = 14 is one of the legs
b = y is unknown
|dw:1469069407344:dw|
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
a^2+b^2 = c^2
14^2+y^2 = 18^2
jimthompson5910 (jim_thompson5910):
hopefully it makes sense how I set up the equation?
OpenStudy (volleyballlover55):
oohhh yes i get it no!!!
OpenStudy (volleyballlover55):
@jim_thompson5910
OpenStudy (volleyballlover55):
let me solve now!
Still Need Help?
Join the QuestionCove community and study together with friends!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (volleyballlover55):
ok so this is the complete answer for part b?
The approximate length of QR is:
a^2+b^2 = c^2
14^2+y^2 = 18^2
196+y^2=324
y2=324−196
y^2=128
y=11.3137
11.3137 rounded to the nearest hundredth is 11.31.
jimthompson5910 (jim_thompson5910):
yes it is
OpenStudy (volleyballlover55):
im not missing anything ? :)
jimthompson5910 (jim_thompson5910):
nope
OpenStudy (volleyballlover55):
yay!
Still Need Help?
Join the QuestionCove community and study together with friends!
Sign Up
jimthompson5910 (jim_thompson5910):
well actually, I would throw in the step sqrt(y^2) = sqrt(128)
other than that, it looks good