LAW ENFORCEMENT: A police accident investigator can use the formula S=2√5L to estimate the speed s of a car in miles per hour based on the length l in feet of the skid marks it left. How fast was a car traveling that left skid marks 129 feet long? Round your answer to the nearest miles per hour
ok, so here you have another function to evaluate, it's just called s, and s = \[2\sqrt{5L}\]
so this evaluates the speed, given the length of the skid marks when the car started to brake, so basically evaluate s when L=129 feet in this case
\[s = 2\sqrt{5(129)}\] plug in the value of L
what do you get?
do i simplify it
yes, you can use a calculator
5 times 129 = 645
thats what i got
when i do it
done
now \[\sqrt{645}\] yields 25.3968
yep
and 2(25.3968) = 50.7937
but the problem says round to the nearest mile per hour, so you can say that the car was traveling at 51 miles per hour
did my answer just get deleted? lol
im doing a review for my exam and nope lol
oops it just didn't refresh haha i see it now
yeah, that was like the previous problems you've done but this time around is just a word problem, make sure you read it and identify the given values so you can compute the function easily
im just not good with word problems
tbh
they can be tricky at times
thank you again
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