What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?
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OpenStudy (samirahdanyel):
OpenStudy (luffingsails):
The first step is to simplify the quadratic. Can you do that?
OpenStudy (samirahdanyel):
yeah i did that
OpenStudy (luffingsails):
\[(2x^2+16x-9) = 0\]
OpenStudy (luffingsails):
What did you get for your answer?
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OpenStudy (samirahdanyel):
OpenStudy (luffingsails):
So, you have the zeros right there. What exactly is the problem?
OpenStudy (samirahdanyel):
its right there in the screenshot
OpenStudy (luffingsails):
Are you trying to get from your answer to the answers provided? If so, then you have to find a common denominator and add them together. That's all they did.
OpenStudy (samirahdanyel):
okay do you have to square root it ?
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OpenStudy (wolf1728):
a=2 b=16 c=-9
x = -b +-sq root(b^2 -4*a*c) / 2*a
x = -16 +-sq root(256 +72) / 4
x = -16 +- sq root(328) / 4
x = -4 +- sq root(328)/4
I messed up - this is the correct answer