Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (samirahdanyel):

What are the zeros of the quadratic function f(x) = 2x2 + 16x – 9?

OpenStudy (samirahdanyel):

OpenStudy (luffingsails):

The first step is to simplify the quadratic. Can you do that?

OpenStudy (samirahdanyel):

yeah i did that

OpenStudy (luffingsails):

\[(2x^2+16x-9) = 0\]

OpenStudy (luffingsails):

What did you get for your answer?

OpenStudy (samirahdanyel):

OpenStudy (luffingsails):

So, you have the zeros right there. What exactly is the problem?

OpenStudy (samirahdanyel):

its right there in the screenshot

OpenStudy (luffingsails):

Are you trying to get from your answer to the answers provided? If so, then you have to find a common denominator and add them together. That's all they did.

OpenStudy (samirahdanyel):

okay do you have to square root it ?

OpenStudy (wolf1728):

a=2 b=16 c=-9 x = -b +-sq root(b^2 -4*a*c) / 2*a x = -16 +-sq root(256 +72) / 4 x = -16 +- sq root(328) / 4 x = -4 +- sq root(328)/4 I messed up - this is the correct answer

OpenStudy (wolf1728):

And yes, you need that square root

OpenStudy (samirahdanyel):

and then you get the square root of 82

OpenStudy (wolf1728):

x = -4 +- [sq root(82*4)/4 ]

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!