Which one of the following does not find the value of f ′(2) for f(x) = x^2 + 3x + 1? A. f'(2)=lim h->0 ( (2+h)^2 + 3(2+h) + 1 -(2)^2 + 3(2) + 1 )/ h B. f'(2)=lim h->0 ( (2+h)^2 + 3(2+h) + 1 -[(2)^2 + 3(2) + 1] )/ h C. f'(2)=lim h->2 (x^2 + 3x + 1 - 11) / (x-2)
or D. all of these find the value for f'(2), but I basically eliminated that one
Could you take a screenshot of the options and attach here ?
Sure
Looks first option and second option are not same. So the false one must be one of them, I guess.
Yeah that's what I was thinking. Would it be the second one?
Nope http://www-rohan.sdsu.edu/~jmahaffy/courses/s00/math121/lectures/limits_cont_deriv/images/limit2.gif
Wait so is h 0? I've never really understood h
\(h\) is not \(0\) I can teach you quick if you want to understand
That'd be awesome
Have you visited any other place/city recently ?
which is far away from your home
Yeah, I have
which place ? starting from your home, how much time did you take to reach that place ?
San Diego, it took about 9 hours
Nice, how far away is it from your home ?
distance...
Oh yes sorry, 2,606 miles
Great! I'm putting everything together in one place : Home to San Diego in 9 hours the distance is 2606 miles
let's draw a graph representing this situation
plot time on x axis and distance travelled on y axis
|dw:1469163427604:dw|
At time = 0 hours, you were at home and the distance travelled is 0 : |dw:1469163478707:dw|
At time = 9 hours, you had reached san diego and the distance travelled is 2606 miles |dw:1469163528618:dw|
With me so far ?
Yeah!
Let's also show how you had traveled the distance in between : |dw:1469163665690:dw|
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