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The following data show the height, in inches, of 11 different garden gnomes: 2 9 1 23 3 7 10 2 10 9 7 After removing the outlier, what does the mean absolute deviation of this data set represent? (4 points) On average, the height of a garden gnome varies 3.2 inches from the mean of 7 inches. On average, the height of a garden gnome varies 3.6 inches from the mean of 6 inches. On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches. On average, the height of a garden gnome varies 3.6 inches from the mean of 7 inches. 5. (08.06)
\[\LARGE{\text{All numbers and equations below are EXAMPLES.}}\] \(\large{\text{outlier}}\): a number outside the range of the rest, example:\[1,8,15,23,58\]58 would be the outlier in this set. \(\large{\text{average}}\): add all the values up and divide by the number of values, example, using previous example set:\[\frac{1+8+15+23+58}{5}\]because there are 5 values in that set.
21
What 21?
Yea add it up then divide it by 5
I just said that \(\large{\text{all those numbers are examples}}\). Why are you using those? Okay, now let's look for the outlier first. What is the outlier in your problem? Here are your digits.
2, 9, 1, 23, 3, 7, 10, 2, 10, 9, 7 Which of these numbers is the \(\text{outlier}\)?
Remember: An outlier is a number that is outside the normal range of the other values. If you had 1, 3, 8, 10 and then 58, your outlier would be 58 because there is not other number in the data set that is even remotely close to 58.
what do i subtract?
Did you take the outlier out yet?
i mean divide by?
83
The outlier is not 83... there is no 83 in the problem
nice new profile picture
Thank you.
2+9+1+23+3+7+10+2+10+9+7
One little thing... you didn't take out the outlier. \[\LARGE{\text{What is the outlier?}}\]
I DONT KNOW
An outlier is a number that is outside the normal range of the other values.
Yep. So what is the outlier in the numbers the problems give you?
nice profile picture
I dont know can you give me the numbers so i can later divide it
Thank you. An outlier is when you have a number that is far away from the other numbers. Does that make more sense?
nice profile picture
not really
nice profile picture
U here ace?
yea
Thank you? Anyway, you need to find a number that is nowhere near the other numbers. That would be the outlier. Here is an \(\large{\text{example}}\): 1, 5, 3, 10, 12, 18, 89 89 is the outlier because it is far away from the other numbers.
Which number in your problem is far away from the other numbers?
hey ace when u gonna email me?
23
Yes! Good job. βΊ
i keep losing connection
Okay, now they want you to take the outlier out, so take the 23 out. Then you can find the average. That's okay, I can wait. Don't worry
what do i divide by?
The number of values there are. How many values (numbers) are left over after you take out the 23?
yea
OK please right the equation im not really getting it FEEL LIKE ITS D
i mean B
I'm helping you get the equation. Slow steps.
How many numbers do you have if you take out the 23?
10
Right. So divide by 10.
What did you get?
2.3
Did you take out the 23 when calculating?
yes 23/10
No, you need to add all the values up then divide by 10 xD
6
You took out the outlier, 23, right? Now you have 2, 9, 1, 3, 7, 10, 2, 10, 9, and 7
yea
Okay, yes. That's the average. Now we need to find the \(\text{difference}\) between the mean and each of those numbers I just mentioned.
I dont know? ;-;
\[\large{60-2=58}\]\[\large{60-9=51}\]\[\large{60-1=58}\]\[60-3=...}\]Keep going. Continue this
is it B C
57
Oops. Last one should be \(\large{60-3}\) Yep. Now keep going down the line. Do this for all the numbers.
6
is it B
Slow steps. We did 60-2, 60-9, 60-1, 60-3. Now do 60-7, 60-10, 60-2, 60-10, 60-9 and 60-7. Make sure you write down each result. --- So far you have 58, 51, 59, 57, from the ones I did for you. What did you get from the rest?
Uhmmmm
wait 1 sec
No problem, take your time βΊ
53, 50, 58, 50, 51, 53
Yes, good job Now we have a new set of data. 58, 51, 59, 57, 53, 50, 58, 50, 51, 53 The mean deviation will be the average (mean) of these numbers.
Remember, you still have 10 values. So you still divide by 10
54
Yep! That should be your mean deviation. βΊ
So its?...C
Oops... there was a typo It was \(\large{six}\), not sixty
Guess we have to do everything over ^-^; Sorry about that
;-;
NO NO NO
Just replace everything we did with 6 instead of 60 and you should get the answer. This link is helpful, try reading it! http://www.mathsisfun.com/data/mean-deviation.html
B!!!!!!
ITS B :)
Did you calculate? xD
YES
and itss right
Yep! βΊ
:d i got it (runs into parents rooms) (screams i got it mom, I GOT IT!!)
Haha xD \[\LARGE{\text{Good job. βΊ}}\]
A student wants to report on the number of books her friends read each week. The collected data are below: 0 24 1 4 5 2 5 4 Which measure of center is most appropriate for this situation and what is its value? (4 points) Median; 2 Median; 4 Mean; 2 Mean; 4 please check this i wrote its B
Measure of center usually means \(median\), considering a median is when you put the numbers in order and find the middle value. What did you get for the median?
btw I think you need to take out 24 because it's an outlier and would throw the data off
Please tell if its right or not i have 5 mins left on the timer
ty
it's wrong
sorry
What is it please fast
there's only one other median answer lol
A?
Yes
Also technically we're not allowed to help on test/quizzes >_>
(08.06) The data set shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks: 8 7 14 10 13 27 11 10 14 7 12 9 14 9 Which of the following statements is true based on the data set? (4 points) There is one outlier that indicates an unusually small number of cars were in the parking lot that day. There are two outliers that indicate an unusually small number of cars were in the parking lot those two days. There is one outlier that indicates an unusually large number of cars were in the parking lot that day. There are two outliers that indicate an unusually large number of cars were in the parking lot those two days. This one is C i wrote
is it?
I think it is
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