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Mathematics 10 Online
OpenStudy (acespeedfighter):

ℍ𝔼𝕃ℙ β„™π•ƒπ”Όπ”Έπ•Šπ”Ό 𝕄𝔼𝔻𝔸𝕃 𝔸ℕ𝔻 𝔽𝔸ℕ

OpenStudy (acespeedfighter):

The following data show the height, in inches, of 11 different garden gnomes: 2 9 1 23 3 7 10 2 10 9 7 After removing the outlier, what does the mean absolute deviation of this data set represent? (4 points) On average, the height of a garden gnome varies 3.2 inches from the mean of 7 inches. On average, the height of a garden gnome varies 3.6 inches from the mean of 6 inches. On average, the height of a garden gnome varies 3.2 inches from the mean of 6 inches. On average, the height of a garden gnome varies 3.6 inches from the mean of 7 inches. 5. (08.06)

OpenStudy (kittiwitti1):

\[\LARGE{\text{All numbers and equations below are EXAMPLES.}}\] \(\large{\text{outlier}}\): a number outside the range of the rest, example:\[1,8,15,23,58\]58 would be the outlier in this set. \(\large{\text{average}}\): add all the values up and divide by the number of values, example, using previous example set:\[\frac{1+8+15+23+58}{5}\]because there are 5 values in that set.

OpenStudy (acespeedfighter):

21

OpenStudy (kittiwitti1):

What 21?

OpenStudy (acespeedfighter):

Yea add it up then divide it by 5

OpenStudy (kittiwitti1):

I just said that \(\large{\text{all those numbers are examples}}\). Why are you using those? Okay, now let's look for the outlier first. What is the outlier in your problem? Here are your digits.

OpenStudy (kittiwitti1):

2, 9, 1, 23, 3, 7, 10, 2, 10, 9, 7 Which of these numbers is the \(\text{outlier}\)?

OpenStudy (kittiwitti1):

Remember: An outlier is a number that is outside the normal range of the other values. If you had 1, 3, 8, 10 and then 58, your outlier would be 58 because there is not other number in the data set that is even remotely close to 58.

OpenStudy (acespeedfighter):

what do i subtract?

OpenStudy (kittiwitti1):

Did you take the outlier out yet?

OpenStudy (acespeedfighter):

i mean divide by?

OpenStudy (acespeedfighter):

83

OpenStudy (kittiwitti1):

The outlier is not 83... there is no 83 in the problem

OpenStudy (acespeedfighter):

nice new profile picture

OpenStudy (kittiwitti1):

Thank you.

OpenStudy (acespeedfighter):

2+9+1+23+3+7+10+2+10+9+7

OpenStudy (kittiwitti1):

One little thing... you didn't take out the outlier. \[\LARGE{\text{What is the outlier?}}\]

OpenStudy (acespeedfighter):

I DONT KNOW

OpenStudy (acespeedfighter):

An outlier is a number that is outside the normal range of the other values.

OpenStudy (kittiwitti1):

Yep. So what is the outlier in the numbers the problems give you?

OpenStudy (acespeedfighter):

nice profile picture

OpenStudy (acespeedfighter):

I dont know can you give me the numbers so i can later divide it

OpenStudy (kittiwitti1):

Thank you. An outlier is when you have a number that is far away from the other numbers. Does that make more sense?

OpenStudy (acespeedfighter):

nice profile picture

OpenStudy (acespeedfighter):

not really

OpenStudy (acespeedfighter):

nice profile picture

OpenStudy (kasey3121):

U here ace?

OpenStudy (acespeedfighter):

yea

OpenStudy (kittiwitti1):

Thank you? Anyway, you need to find a number that is nowhere near the other numbers. That would be the outlier. Here is an \(\large{\text{example}}\): 1, 5, 3, 10, 12, 18, 89 89 is the outlier because it is far away from the other numbers.

OpenStudy (kittiwitti1):

Which number in your problem is far away from the other numbers?

OpenStudy (kasey3121):

hey ace when u gonna email me?

OpenStudy (acespeedfighter):

23

OpenStudy (kittiwitti1):

Yes! Good job. ☺

OpenStudy (acespeedfighter):

i keep losing connection

OpenStudy (kittiwitti1):

Okay, now they want you to take the outlier out, so take the 23 out. Then you can find the average. That's okay, I can wait. Don't worry

OpenStudy (acespeedfighter):

what do i divide by?

OpenStudy (kittiwitti1):

The number of values there are. How many values (numbers) are left over after you take out the 23?

OpenStudy (acespeedfighter):

yea

OpenStudy (acespeedfighter):

OK please right the equation im not really getting it FEEL LIKE ITS D

OpenStudy (acespeedfighter):

i mean B

OpenStudy (kittiwitti1):

I'm helping you get the equation. Slow steps.

OpenStudy (kittiwitti1):

How many numbers do you have if you take out the 23?

OpenStudy (acespeedfighter):

10

OpenStudy (kittiwitti1):

Right. So divide by 10.

OpenStudy (kittiwitti1):

What did you get?

OpenStudy (acespeedfighter):

2.3

OpenStudy (kittiwitti1):

Did you take out the 23 when calculating?

OpenStudy (acespeedfighter):

yes 23/10

OpenStudy (kittiwitti1):

No, you need to add all the values up then divide by 10 xD

OpenStudy (acespeedfighter):

6

OpenStudy (kittiwitti1):

You took out the outlier, 23, right? Now you have 2, 9, 1, 3, 7, 10, 2, 10, 9, and 7

OpenStudy (acespeedfighter):

yea

OpenStudy (kittiwitti1):

Okay, yes. That's the average. Now we need to find the \(\text{difference}\) between the mean and each of those numbers I just mentioned.

OpenStudy (acespeedfighter):

I dont know? ;-;

OpenStudy (kittiwitti1):

\[\large{60-2=58}\]\[\large{60-9=51}\]\[\large{60-1=58}\]\[60-3=...}\]Keep going. Continue this

OpenStudy (acespeedfighter):

is it B C

OpenStudy (acespeedfighter):

57

OpenStudy (kittiwitti1):

Oops. Last one should be \(\large{60-3}\) Yep. Now keep going down the line. Do this for all the numbers.

OpenStudy (acespeedfighter):

6

OpenStudy (acespeedfighter):

is it B

OpenStudy (kittiwitti1):

Slow steps. We did 60-2, 60-9, 60-1, 60-3. Now do 60-7, 60-10, 60-2, 60-10, 60-9 and 60-7. Make sure you write down each result. --- So far you have 58, 51, 59, 57, from the ones I did for you. What did you get from the rest?

OpenStudy (acespeedfighter):

Uhmmmm

OpenStudy (acespeedfighter):

wait 1 sec

OpenStudy (kittiwitti1):

No problem, take your time ☺

OpenStudy (acespeedfighter):

53, 50, 58, 50, 51, 53

OpenStudy (kittiwitti1):

Yes, good job Now we have a new set of data. 58, 51, 59, 57, 53, 50, 58, 50, 51, 53 The mean deviation will be the average (mean) of these numbers.

OpenStudy (kittiwitti1):

Remember, you still have 10 values. So you still divide by 10

OpenStudy (acespeedfighter):

54

OpenStudy (kittiwitti1):

Yep! That should be your mean deviation. ☺

OpenStudy (acespeedfighter):

So its?...C

OpenStudy (kittiwitti1):

Oops... there was a typo It was \(\large{six}\), not sixty

OpenStudy (kittiwitti1):

Guess we have to do everything over ^-^; Sorry about that

OpenStudy (acespeedfighter):

;-;

OpenStudy (acespeedfighter):

NO NO NO

OpenStudy (kittiwitti1):

Just replace everything we did with 6 instead of 60 and you should get the answer. This link is helpful, try reading it! http://www.mathsisfun.com/data/mean-deviation.html

OpenStudy (acespeedfighter):

B!!!!!!

OpenStudy (acespeedfighter):

ITS B :)

OpenStudy (kittiwitti1):

Did you calculate? xD

OpenStudy (acespeedfighter):

YES

OpenStudy (acespeedfighter):

and itss right

OpenStudy (kittiwitti1):

Yep! ☺

OpenStudy (acespeedfighter):

:d i got it (runs into parents rooms) (screams i got it mom, I GOT IT!!)

OpenStudy (kittiwitti1):

Haha xD \[\LARGE{\text{Good job. ☺}}\]

OpenStudy (acespeedfighter):

A student wants to report on the number of books her friends read each week. The collected data are below: 0 24 1 4 5 2 5 4 Which measure of center is most appropriate for this situation and what is its value? (4 points) Median; 2 Median; 4 Mean; 2 Mean; 4 please check this i wrote its B

OpenStudy (kittiwitti1):

Measure of center usually means \(median\), considering a median is when you put the numbers in order and find the middle value. What did you get for the median?

OpenStudy (kittiwitti1):

btw I think you need to take out 24 because it's an outlier and would throw the data off

OpenStudy (acespeedfighter):

Please tell if its right or not i have 5 mins left on the timer

OpenStudy (acespeedfighter):

ty

OpenStudy (kittiwitti1):

it's wrong

OpenStudy (kittiwitti1):

sorry

OpenStudy (acespeedfighter):

What is it please fast

OpenStudy (kittiwitti1):

there's only one other median answer lol

OpenStudy (acespeedfighter):

A?

OpenStudy (kittiwitti1):

Yes

OpenStudy (kittiwitti1):

Also technically we're not allowed to help on test/quizzes >_>

OpenStudy (acespeedfighter):

(08.06) The data set shows the number of cars parked in the restaurant parking lot during the lunch hour each day for two weeks: 8 7 14 10 13 27 11 10 14 7 12 9 14 9 Which of the following statements is true based on the data set? (4 points) There is one outlier that indicates an unusually small number of cars were in the parking lot that day. There are two outliers that indicate an unusually small number of cars were in the parking lot those two days. There is one outlier that indicates an unusually large number of cars were in the parking lot that day. There are two outliers that indicate an unusually large number of cars were in the parking lot those two days. This one is C i wrote

OpenStudy (acespeedfighter):

is it?

OpenStudy (kittiwitti1):

I think it is

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