The manager of a grocery store reports that there is a 12 percent chance that a customer buys apples during a shopping trip, a 5 percent chance that a customer buy apples and carrots, and a 17 percent chance that a customer buys apples or carrots.
What is the probability of a customer buying carrots?
percent
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jimthompson5910 (jim_thompson5910):
hint:
P(A and B) = P(A) + P(B) - P(A or B)
OpenStudy (samirahdanyel):
so it would be p (12 and 17) =P(12)+P(17)-P(12-17)
jimthompson5910 (jim_thompson5910):
A = event person buys apples
B = event person buys carrots
`The manager of a grocery store reports that there is a 12 percent chance that a customer buys apples during a shopping trip` means P(A) = 0.12
`...5 percent chance that a customer buy apples and carrots` so P(A and B) = 0.05
`...7 percent chance that a customer buys apples or carrots.` so P(A or B) = 0.07
jimthompson5910 (jim_thompson5910):
let x = P(B)
OpenStudy (samirahdanyel):
i got 0.10
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jimthompson5910 (jim_thompson5910):
using the info above, we can go from
P(A and B) = P(A) + P(B) - P(A or B)
to
0.05 = 0.12 + x - 0.07
OpenStudy (samirahdanyel):
do we have to solve this equation
jimthompson5910 (jim_thompson5910):
my bad, I meant to say 0.17 instead of 0.07
jimthompson5910 (jim_thompson5910):
0.05 = 0.12 + x - 0.17 is the equation you need to solve
jimthompson5910 (jim_thompson5910):
solving 0.05 = 0.12 + x - 0.17 for x gives x = 0.10 so you are correct
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OpenStudy (samirahdanyel):
i got 1/10
OpenStudy (samirahdanyel):
so its 10 percent?
jimthompson5910 (jim_thompson5910):
so 10%
jimthompson5910 (jim_thompson5910):
yep
OpenStudy (samirahdanyel):
thank you for your help
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