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The table below represents the velocity of a car as a function of time: Time (hour) x Velocity (miles/hours) y 0 50 1 52 2 54 3 56 Part A: What is the y-intercept of the function, and what does this tell you about the car? (4 points) Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points) Part C: What would be the domain of the function if the velocity of the car was measured until it reached 60 miles/hour and the car does not change motion? (2 points)
Let's focus on part A for now `Part A: What is the y-intercept of the function, and what does this tell you about the car? (4 points)` to find the y intercept, look at the row that has x = 0. What is the corresponding paired y value for when x = 0?
would it be 50
yes, so that's the y intercept
any guesses of what it means in terms of the problem?
the time and velocity
x = 0 means the time is 0 hours y = 50 means the velocity is 50 mph
time = 0 hours is the lowest the time value can go, so it is the starting point or the initial time value
oh yea that make sense
this means that 50 mph is the initial velocity
so that would be the end to part a right
yes
ready for part B?
yes
Time (hour) x Velocity (miles/hours) y 0 50 1 52 2 54 3 56 Part B: Calculate the average rate of change of the function represented by the table between x = 1 to x = 3 hours, and tell what the average rate represents. (4 points)
when x = 1, what is the value of y?
i am not sure
Look at the table. Locate '1' in the x column. What is right beside it?
52
yes
so x = 1 and y = 52 pair up we have the ordered pair (x,y) = (1,52) make sense?
yep
when x = 3, what is the corresponding value of y?
56
so (x,y) = (3,56) is another point
we have these two points (1,52) and (3,56) are you able to determine the slope of the line through those points?
would i use the equation y2-y1/x2-x1
yes \[\Large m = \frac{y_2 - y_1}{x_2 - x_1}\]
4/2
reduce that to get what?
2/1
which simplifies to just 2
so the average rate of change (from x = 1 to x = 3) is 2 this means that for each increase in the number of hours (x), the velocity (y) is increasing by 2 mph
this is known as the acceleration
so would that be the end of part 2
yes that wraps up part B
can we start part c
`Part C: What would be the domain of the function if the velocity of the car was measured until it reached 60 miles/hour and the car does not change motion? (2 points)`
let's look at the table again Time (hour) x Velocity (miles/hours) y 0 50 1 52 2 54 3 56
what would be the y value for when x = 4? Any ideas?
hint: notice how each time x increases by 1, y will increase by 2 (hence the slope of 2/1 = 2)
will you explain with more depth
one pair is x = 0 and y = 50 another pair right underneath is x = 1 and y = 52 notice how x increases by 1 (going from x = 0 to x = 1) at the same time, y increases by 2 (going from y = 50 to y = 52) do you observe this pattern?
wait hold on.
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