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Mathematics 8 Online
OpenStudy (mayankdevnani):

@desmarie

OpenStudy (mayankdevnani):

\[\large \bf 2y^2+6y-8=0 \]

OpenStudy (desmarie):

ok

OpenStudy (mayankdevnani):

want to use it by general method or by formula ?

OpenStudy (desmarie):

either

OpenStudy (mayankdevnani):

okay lets start by general method

OpenStudy (kingogcobraxx):

you already said the answer was "a" to that one but have fun with that

OpenStudy (mayankdevnani):

divide the whole equation by 2

OpenStudy (desmarie):

y^2 + 3y - 4

OpenStudy (mayankdevnani):

good

OpenStudy (mayankdevnani):

\[\large \bf ax^2+bx+c=0\] the two roots will satisfy say `x` and `y`when \[\large \bf xy=ab\] and \[\large \bf x+y=b\]

OpenStudy (mayankdevnani):

so \[\large \bf y^2+3y-4=0\] \[\large \bf xy=-4~\And~x+y=3\]

OpenStudy (mayankdevnani):

can you find out the value of x and y ?

OpenStudy (desmarie):

lol...prob not

OpenStudy (mayankdevnani):

figure all the factors of -4 \[\large \bf -4=1 \times -4=-2 \times 2 \]

OpenStudy (mayankdevnani):

-4=1*-4 = -2*2 = 2*-2 =-1*4

OpenStudy (mayankdevnani):

from these factors,tell me which staisfy x+y=3

OpenStudy (mayankdevnani):

*satisfy

OpenStudy (mayankdevnani):

you there ? @desmarie

OpenStudy (desmarie):

lol....sorta

OpenStudy (mayankdevnani):

tell me

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