Mathematics
8 Online
OpenStudy (mayankdevnani):
@desmarie
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OpenStudy (mayankdevnani):
\[\large \bf 2y^2+6y-8=0 \]
OpenStudy (desmarie):
ok
OpenStudy (mayankdevnani):
want to use it by general method or by formula ?
OpenStudy (desmarie):
either
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OpenStudy (mayankdevnani):
okay lets start by general method
OpenStudy (kingogcobraxx):
you already said the answer was "a" to that one but have fun with that
OpenStudy (mayankdevnani):
divide the whole equation by 2
OpenStudy (desmarie):
y^2 + 3y - 4
OpenStudy (mayankdevnani):
good
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OpenStudy (mayankdevnani):
\[\large \bf ax^2+bx+c=0\]
the two roots will satisfy say `x` and `y`when
\[\large \bf xy=ab\]
and
\[\large \bf x+y=b\]
OpenStudy (mayankdevnani):
so \[\large \bf y^2+3y-4=0\]
\[\large \bf xy=-4~\And~x+y=3\]
OpenStudy (mayankdevnani):
can you find out the value of x and y ?
OpenStudy (desmarie):
lol...prob not
OpenStudy (mayankdevnani):
figure all the factors of -4
\[\large \bf -4=1 \times -4=-2 \times 2 \]
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OpenStudy (mayankdevnani):
-4=1*-4 = -2*2 = 2*-2 =-1*4
OpenStudy (mayankdevnani):
from these factors,tell me which staisfy x+y=3
OpenStudy (mayankdevnani):
*satisfy
OpenStudy (mayankdevnani):
you there ? @desmarie
OpenStudy (desmarie):
lol....sorta
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OpenStudy (mayankdevnani):
tell me