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Mathematics 15 Online
OpenStudy (volleyballlover55):

help

OpenStudy (volleyballlover55):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

first you'll need an equation for machine C

jimthompson5910 (jim_thompson5910):

what two points are in the table?

OpenStudy (volleyballlover55):

2,150 4,300

jimthompson5910 (jim_thompson5910):

don't forget parenthesis

OpenStudy (volleyballlover55):

ok

OpenStudy (volleyballlover55):

(2,150) (4,300)

jimthompson5910 (jim_thompson5910):

what is the slope of the line through those points?

OpenStudy (volleyballlover55):

y: 150 and 300 x: 2 and 4 -150 and -2 75

jimthompson5910 (jim_thompson5910):

good, the slope is 75

jimthompson5910 (jim_thompson5910):

m = 75 will be plugged into y = mx+b to get y = 75*x + b

jimthompson5910 (jim_thompson5910):

let's pick one of the ordered pairs, say (2,150) plug in x = 2 and y = 150 to go from this y = 75*x + b to this 150 = 75*2 + b now solve for b

OpenStudy (volleyballlover55):

ok.. i got x= -b/75 +2

jimthompson5910 (jim_thompson5910):

150 = 75*2 + b 150 = 150 + b b = ???

OpenStudy (volleyballlover55):

b=0! @jim_thompson5910

jimthompson5910 (jim_thompson5910):

yep b = 0

jimthompson5910 (jim_thompson5910):

y = 75*x + b will turn into y = 75*x + 0 which simplifies to y = 75x

jimthompson5910 (jim_thompson5910):

So the equation for machine C is y = 75x

OpenStudy (volleyballlover55):

ok so the answer is 75?

jimthompson5910 (jim_thompson5910):

no

jimthompson5910 (jim_thompson5910):

equation for machine C is y = 75x plug in x = 11 to get y = ???

OpenStudy (volleyballlover55):

ok

jimthompson5910 (jim_thompson5910):

y = 75*x y = 75*11 y = ???

OpenStudy (volleyballlover55):

825

jimthompson5910 (jim_thompson5910):

yes, now plug x = 11 into y = 130x to get y = ???

OpenStudy (volleyballlover55):

wait what is it?

OpenStudy (volleyballlover55):

whats the equation

OpenStudy (volleyballlover55):

what do you mean "plug x = 11 into y = 130x "?

jimthompson5910 (jim_thompson5910):

replace x with 11 y = 130*x y = 130*11 y = ???

OpenStudy (volleyballlover55):

1430

jimthompson5910 (jim_thompson5910):

now subtract 1430 - 825 = 605

jimthompson5910 (jim_thompson5910):

605 is the answer

OpenStudy (volleyballlover55):

ok awesome! next :)

OpenStudy (volleyballlover55):

jimthompson5910 (jim_thompson5910):

I want to see if you can try this one on your own

jimthompson5910 (jim_thompson5910):

Don't just give out the answer. Show me your steps (specifically the slope and y intercept)

OpenStudy (volleyballlover55):

ok is it the same steps as the last one

jimthompson5910 (jim_thompson5910):

yes the goal is to find the equation in the form y = mx+b

OpenStudy (volleyballlover55):

ok

OpenStudy (volleyballlover55):

so the first thing is to find the pairs.. (1,78) (2,86)

jimthompson5910 (jim_thompson5910):

so far, so good

OpenStudy (volleyballlover55):

ok y: 78 and 86 x: 1 and 2

jimthompson5910 (jim_thompson5910):

then what?

OpenStudy (volleyballlover55):

then : -8 -1

jimthompson5910 (jim_thompson5910):

good, then what comes next?

OpenStudy (volleyballlover55):

then divide and you get 8

jimthompson5910 (jim_thompson5910):

yes, so that is the slope

jimthompson5910 (jim_thompson5910):

what comes next?

OpenStudy (volleyballlover55):

78=8*1+b b=70

jimthompson5910 (jim_thompson5910):

very nice

jimthompson5910 (jim_thompson5910):

m = 8 and b = 70 so the equation y = mx+b turns into y = 8x+70

OpenStudy (volleyballlover55):

ok so thats the answer?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (volleyballlover55):

ok next!

OpenStudy (volleyballlover55):

jimthompson5910 (jim_thompson5910):

it's asking for the slope

OpenStudy (volleyballlover55):

ok so whats the first step?

jimthompson5910 (jim_thompson5910):

what two points do you see?

jimthompson5910 (jim_thompson5910):

look at the graph

OpenStudy (volleyballlover55):

(1,35) (2,70)

jimthompson5910 (jim_thompson5910):

good, find the slope of the line through those two points

OpenStudy (volleyballlover55):

y: 35 and 70 x: 1 and 2 -35 and -1 35

jimthompson5910 (jim_thompson5910):

Yes the slope is 35. So that wraps up the problem.

jimthompson5910 (jim_thompson5910):

Be sure to show how you're dividing and subtracting

OpenStudy (volleyballlover55):

awesome! next The equation shows the relationship between x and y: y = −2x + 11 What is the slope of the equation? −11 −2 9 11

jimthompson5910 (jim_thompson5910):

you tell me

OpenStudy (volleyballlover55):

well how do we figure it out?

jimthompson5910 (jim_thompson5910):

y = mx+b the m in front of the x is the slope

jimthompson5910 (jim_thompson5910):

example: y = 7x-10 has a slope of 7 because the 7 is in front of the x

OpenStudy (volleyballlover55):

oh so the slope is -2?

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (volleyballlover55):

ok next! One triangle on a graph has a vertical side of 7 and a horizontal side of 12. Another triangle on a graph has a vertical side of 28 and a horizontal side of 48. Could the hypotenuses of these two triangles lie along the same line? Yes, because they are similar triangles Yes, because all triangles can fit along this line No, because they need to be the same size No, because they are not similar triangles

jimthompson5910 (jim_thompson5910):

another one to practice with: what is the slope of y = 5x+23 ?

OpenStudy (volleyballlover55):

5

jimthompson5910 (jim_thompson5910):

good

OpenStudy (volleyballlover55):

so can we move onto the next question please.. One triangle on a graph has a vertical side of 7 and a horizontal side of 12. Another triangle on a graph has a vertical side of 28 and a horizontal side of 48. Could the hypotenuses of these two triangles lie along the same line? Yes, because they are similar triangles Yes, because all triangles can fit along this line No, because they need to be the same size No, because they are not similar triangles

jimthompson5910 (jim_thompson5910):

`One triangle on a graph has a vertical side of 7 and a horizontal side of 12. ` rise =7 run = 12 slope = rise/run = 7/12 what is the other slope (of the other triangle hypotenuse)?

OpenStudy (volleyballlover55):

28/48?

jimthompson5910 (jim_thompson5910):

reduce 28/48 to get what?

OpenStudy (volleyballlover55):

7/12

jimthompson5910 (jim_thompson5910):

yes, the slopes are the same, so it is possible to line up the two hypotenuses

OpenStudy (volleyballlover55):

yes

jimthompson5910 (jim_thompson5910):

put another way, ` Yes, because they are similar triangles` which is the answer

OpenStudy (volleyballlover55):

ok next!

jimthompson5910 (jim_thompson5910):

they want you to find the slope for part A they also want the initial value for part A

OpenStudy (volleyballlover55):

ok..

jimthompson5910 (jim_thompson5910):

what two points are in the table?

OpenStudy (volleyballlover55):

(2005,1200) (2008,1350)

jimthompson5910 (jim_thompson5910):

let's make x = number of years since 2005 so x = 0 would represent the year 2005 x = 3 would represent the year 2008 since it's 3 years later

jimthompson5910 (jim_thompson5910):

so we'd have these two points (0,1200) and (3,1350)

OpenStudy (volleyballlover55):

OK...

jimthompson5910 (jim_thompson5910):

what is the slope of the line through (0,1200) and (3,1350)

OpenStudy (volleyballlover55):

y: 1200, 1350 x: 0,3

jimthompson5910 (jim_thompson5910):

keep going

OpenStudy (volleyballlover55):

-150 and -1

OpenStudy (volleyballlover55):

im sorry i meant -3

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