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OpenStudy (volleyballlover55):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
first you'll need an equation for machine C
jimthompson5910 (jim_thompson5910):
what two points are in the table?
OpenStudy (volleyballlover55):
2,150
4,300
jimthompson5910 (jim_thompson5910):
don't forget parenthesis
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OpenStudy (volleyballlover55):
ok
OpenStudy (volleyballlover55):
(2,150)
(4,300)
jimthompson5910 (jim_thompson5910):
what is the slope of the line through those points?
OpenStudy (volleyballlover55):
y:
150 and 300
x:
2 and 4
-150 and -2
75
jimthompson5910 (jim_thompson5910):
good, the slope is 75
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jimthompson5910 (jim_thompson5910):
m = 75 will be plugged into y = mx+b to get y = 75*x + b
jimthompson5910 (jim_thompson5910):
let's pick one of the ordered pairs, say (2,150)
plug in x = 2 and y = 150
to go from this
y = 75*x + b
to this
150 = 75*2 + b
now solve for b
OpenStudy (volleyballlover55):
ok.. i got
x= -b/75 +2
jimthompson5910 (jim_thompson5910):
150 = 75*2 + b
150 = 150 + b
b = ???
OpenStudy (volleyballlover55):
b=0! @jim_thompson5910
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jimthompson5910 (jim_thompson5910):
yep b = 0
jimthompson5910 (jim_thompson5910):
y = 75*x + b
will turn into
y = 75*x + 0
which simplifies to
y = 75x
jimthompson5910 (jim_thompson5910):
So the equation for machine C is y = 75x
OpenStudy (volleyballlover55):
ok so the answer is 75?
jimthompson5910 (jim_thompson5910):
no
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jimthompson5910 (jim_thompson5910):
equation for machine C is y = 75x
plug in x = 11 to get y = ???
OpenStudy (volleyballlover55):
ok
jimthompson5910 (jim_thompson5910):
y = 75*x
y = 75*11
y = ???
OpenStudy (volleyballlover55):
825
jimthompson5910 (jim_thompson5910):
yes, now plug x = 11 into y = 130x to get y = ???
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OpenStudy (volleyballlover55):
wait what is it?
OpenStudy (volleyballlover55):
whats the equation
OpenStudy (volleyballlover55):
what do you mean "plug x = 11 into y = 130x "?
jimthompson5910 (jim_thompson5910):
replace x with 11
y = 130*x
y = 130*11
y = ???
OpenStudy (volleyballlover55):
1430
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jimthompson5910 (jim_thompson5910):
now subtract
1430 - 825 = 605
jimthompson5910 (jim_thompson5910):
605 is the answer
OpenStudy (volleyballlover55):
ok awesome! next :)
OpenStudy (volleyballlover55):
jimthompson5910 (jim_thompson5910):
I want to see if you can try this one on your own
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jimthompson5910 (jim_thompson5910):
Don't just give out the answer. Show me your steps (specifically the slope and y intercept)
OpenStudy (volleyballlover55):
ok is it the same steps as the last one
jimthompson5910 (jim_thompson5910):
yes the goal is to find the equation in the form y = mx+b
OpenStudy (volleyballlover55):
ok
OpenStudy (volleyballlover55):
so the first thing is to find the pairs..
(1,78)
(2,86)
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jimthompson5910 (jim_thompson5910):
so far, so good
OpenStudy (volleyballlover55):
ok
y:
78 and 86
x:
1 and 2
jimthompson5910 (jim_thompson5910):
then what?
OpenStudy (volleyballlover55):
then :
-8
-1
jimthompson5910 (jim_thompson5910):
good, then what comes next?
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OpenStudy (volleyballlover55):
then divide and you get 8
jimthompson5910 (jim_thompson5910):
yes, so that is the slope
jimthompson5910 (jim_thompson5910):
what comes next?
OpenStudy (volleyballlover55):
78=8*1+b
b=70
jimthompson5910 (jim_thompson5910):
very nice
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jimthompson5910 (jim_thompson5910):
m = 8 and b = 70 so the equation y = mx+b turns into y = 8x+70
OpenStudy (volleyballlover55):
ok so thats the answer?
jimthompson5910 (jim_thompson5910):
yes
OpenStudy (volleyballlover55):
ok next!
OpenStudy (volleyballlover55):
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jimthompson5910 (jim_thompson5910):
it's asking for the slope
OpenStudy (volleyballlover55):
ok so whats the first step?
jimthompson5910 (jim_thompson5910):
what two points do you see?
jimthompson5910 (jim_thompson5910):
look at the graph
OpenStudy (volleyballlover55):
(1,35)
(2,70)
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jimthompson5910 (jim_thompson5910):
good, find the slope of the line through those two points
OpenStudy (volleyballlover55):
y:
35 and 70
x:
1 and 2
-35 and -1
35
jimthompson5910 (jim_thompson5910):
Yes the slope is 35. So that wraps up the problem.
jimthompson5910 (jim_thompson5910):
Be sure to show how you're dividing and subtracting
OpenStudy (volleyballlover55):
awesome! next
The equation shows the relationship between x and y:
y = −2x + 11
What is the slope of the equation?
−11
−2
9
11
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jimthompson5910 (jim_thompson5910):
you tell me
OpenStudy (volleyballlover55):
well how do we figure it out?
jimthompson5910 (jim_thompson5910):
y = mx+b
the m in front of the x is the slope
jimthompson5910 (jim_thompson5910):
example: y = 7x-10 has a slope of 7 because the 7 is in front of the x
OpenStudy (volleyballlover55):
oh so the slope is -2?
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jimthompson5910 (jim_thompson5910):
yes
OpenStudy (volleyballlover55):
ok next!
One triangle on a graph has a vertical side of 7 and a horizontal side of 12. Another triangle on a graph has a vertical side of 28 and a horizontal side of 48.
Could the hypotenuses of these two triangles lie along the same line?
Yes, because they are similar triangles
Yes, because all triangles can fit along this line
No, because they need to be the same size
No, because they are not similar triangles
jimthompson5910 (jim_thompson5910):
another one to practice with: what is the slope of y = 5x+23 ?
OpenStudy (volleyballlover55):
5
jimthompson5910 (jim_thompson5910):
good
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OpenStudy (volleyballlover55):
so can we move onto the next question please..
One triangle on a graph has a vertical side of 7 and a horizontal side of 12. Another triangle on a graph has a vertical side of 28 and a horizontal side of 48.
Could the hypotenuses of these two triangles lie along the same line?
Yes, because they are similar triangles
Yes, because all triangles can fit along this line
No, because they need to be the same size
No, because they are not similar triangles
jimthompson5910 (jim_thompson5910):
`One triangle on a graph has a vertical side of 7 and a horizontal side of 12. `
rise =7
run = 12
slope = rise/run = 7/12
what is the other slope (of the other triangle hypotenuse)?
OpenStudy (volleyballlover55):
28/48?
jimthompson5910 (jim_thompson5910):
reduce 28/48 to get what?
OpenStudy (volleyballlover55):
7/12
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jimthompson5910 (jim_thompson5910):
yes, the slopes are the same, so it is possible to line up the two hypotenuses
OpenStudy (volleyballlover55):
yes
jimthompson5910 (jim_thompson5910):
put another way, ` Yes, because they are similar triangles` which is the answer
OpenStudy (volleyballlover55):
ok next!
jimthompson5910 (jim_thompson5910):
they want you to find the slope for part A
they also want the initial value for part A
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OpenStudy (volleyballlover55):
ok..
jimthompson5910 (jim_thompson5910):
what two points are in the table?
OpenStudy (volleyballlover55):
(2005,1200)
(2008,1350)
jimthompson5910 (jim_thompson5910):
let's make x = number of years since 2005
so x = 0 would represent the year 2005
x = 3 would represent the year 2008 since it's 3 years later
jimthompson5910 (jim_thompson5910):
so we'd have these two points (0,1200) and (3,1350)
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OpenStudy (volleyballlover55):
OK...
jimthompson5910 (jim_thompson5910):
what is the slope of the line through (0,1200) and (3,1350)
OpenStudy (volleyballlover55):
y:
1200, 1350
x:
0,3
jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (volleyballlover55):
-150 and -1
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