Someone PLZZZZZ HELPPP ME ON A TEST I WILL MEDAL AND FAN!!!! Create your own factorable polynomial with a GCF. Rewrite that polynomial in two other equivalent forms. Explain how each form was created.
Start with this one and use it as an example. I will explain as I go along, ok?
Ok.
\[2x ^{2}+2x-12\]
There is a greatest common factor of 2 in there, see?
Yes.
Ok, so if you factor it as it is, you get the products (x + 3)(2x - 4)
The first equation You gave me.
Yes. I'm only using the one equation. There are 2 different factorizations for it because it has a GCF
Ok I think I got it now.
Do you need me anymore or are you good from here?
I'm good I will let you know if I need help. With more.
I got 2(x-2)(x+3)
Actually you got the signs wrong. The 3 has to be negative because the 6 is negative in the polynomial. There are 2 different factorizations for that. Fix this one and there is still the other one, the one without reducing it first.
But when I plugged it in I got the same thing as the first equation so i'm not getting it right now. :'(
@IMStuck
Sorry, I was on another problem! When you factor out the 2 first you get the products 2(x-3)(x+2)
When you don't factor out the 2 first you get (2x-4)(x+3)
The instructions were to create you own polynomial with a GCF. You did that. Next it says to show 2 other equivalent forms. Factoring out the 2 leaves you with: \[2(x ^{2}+x-6)\]
That's one form. The other is to either factor what's left after you take out the 2, or factor it with the 2 in it. I'm not sure what they are asking for specifically. Factoring out the 2 is one way to show it in a different form. Then factoring what's left is probably what they mean by the other way. I would say your answers would be this:
\[2(x ^{2}+x-6)\] and \[(2x-4)(x+3)\]
Does that go along with what you are studying in school right now?
Yes.
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