need help graphing

Question

need help graphing

jdanmath · Answer

$$y=3^{1-x}$$

jdanmath · Answer

i dont understand why it shifts to the right one when 1 is postive - shouldn't it go to the left?

thesmartone · Answer

$$y = 3^{-x+1}=y=3^{-(x-1)}$$ mhmm, this is interesting. I'm looking at all the graphs to see a correlation mhmm https://www.desmos.com/calculator/qqg6rbxnn4

mathstudent55 · Answer

@TheSmartOne
You got it.

Start with 

$\large y = 3^{-(x)} $

Then 

$\large y = 3^{1-x} $

can be rewritten as 

$\large y = 3^{-x + 1} $

$\large y = 3^{-(x - 1)} $

Now compare $\large y = 3^{-(x - 1)} $ to $\large y = 3^{-(x)} $.

You see that x was replaced with x - 1.
When x is replaced with x - h, the graph shifts h units horizontally. It shifts to the right when h is positive, and it shifts to the left when h is negative. When you compare x - h to x - 1, you see that h = 1, a positive number, so the shift is to the right.

fibonaccichick666 · Answer

Think of it like this
$$y=3^{-x+1}=3^{-x}*3=\frac{1}{3^{x-1}}$$

fibonaccichick666 · Answer

now in order to make it =1 x would have to equal 1 yea? But if we compare it to $\frac{1}{3^x}$ x would need to =0 for that to equal 1.  So, it moved 1 positive unit (or to the right)