Question

(Probability): The figure below shows a shaded rectangular region inside a large rectangle:

Answer 1

What is the probability that a point chosen inside the large rectangle is not in the shaded region?
42%
58%
72%
84%

Answer 2

old people gathering today?

Answer 3

Well start by finding the area of the large and small rectangles.
\[A_\left( s \right)=3\times 7\]\[A_\left( l \right)=5\times 10\]

Answer 4

what is A(8) and A(I)?

Answer 5

To find the area of the non shaded region we can say
\[A_\left( l \right)-A_\left( s \right)=A_\left( sr \right)\]

Answer 6

Ok so im saying that
\[A_\left( s \right)\] represents the area of the smaller rectangle \[A_\left( l \right)\] represents the area of the larger rectangle and \[A_\left( sr \right)\] represents the area of the shaded region

Answer 7

Alright

Answer 8

*\[A_\left( sr \right)\] actually represents the non-shaded region

Answer 9

A(s) = 21 A(l)= 50

Answer 10

Ok so
50-21 = Area of the non shaded region

Answer 11

A(sl)= 29

Answer 12

sr*

Answer 13

Now the probability that a point is chosen is not in the shaded region is equivalent to the
area of the non shaded region divided by the area of the larger rectangle so
\[\frac{ 29 }{ 50 }=\]

Answer 14

Divide?

Answer 15

yes 29 divided by 50

Answer 16

58%

Answer 17

Which will give you a decimal answer which you will then need to multiply by 100%

Answer 18

yes correct

Answer 19

Thanks

Answer 20

ya np