Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (abbles):

Inverse trig question

OpenStudy (abbles):

Why does arctan(-sqrt3) equal -pi/3 instead of 5pi/3?

OpenStudy (abbles):

Arccos(-1/2) equals 2pi/3...

OpenStudy (faiqraees):

Because negative indicates you're moving clockwise instead of anticlockwise

OpenStudy (abbles):

What's the difference though?

OpenStudy (faiqraees):

Difference between what?

OpenStudy (abbles):

If tan(5pi/3) equals -sqrt3, why isn't 5pi/3 the answer?

OpenStudy (faiqraees):

Well because trigonometric functions can give many values for one input like arccos 0 =1/2 pi , 2.5pi, 5 pi and so on

OpenStudy (abbles):

Sorry, I'm not following... Are you saying that 5pi/3 would have multiple values?

OpenStudy (faiqraees):

I am saying arctan(-sqrt3) has many values

OpenStudy (abbles):

The relation has many values, but the function only has one value doesn't it? :/

OpenStudy (abbles):

It should have a capital A.. which means the function of inverse tangent, not the relation..

OpenStudy (faiqraees):

Is the range for the angle defined?

OpenStudy (abbles):

This is the actual question: Evaluate the expression Arctan(-sqrt3). Give the exact value. And the answer was -pi/3 I'm trying to understand why it was -pi/3 instead of 5pi/3

OpenStudy (abbles):

No, it doesn't specify a range. But the capital A means the range is restricted.

OpenStudy (faiqraees):

Well both answer are correct But remember a property tan (-theta) = -tan(theta)

OpenStudy (faiqraees):

Well both answer are correct But remember a property arctan (-theta) = -arctan(theta)

OpenStudy (abbles):

Are there different properties for cos and sin?

OpenStudy (abbles):

Because Arccos(-1/2) is 2pi/3, not a negative number....

zepdrix (zepdrix):

|dw:1469651450031:dw|well imagine if we made the restriction 1st and 4th quadrant for tangent. That would look kind of awkward, wouldn't it?

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!