If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0°C to 97.0°C, what mass is the sample of aluminum? (The specific heat of aluminum is 0.90 J/(g × °C).)

0.10 g

10.0 g

12.0 g

57.7 g

Question

If 832J of energy is required to raise the temperature of a sample of aluminum from 20.0°C to 97.0°C, what mass is the sample of aluminum? (The specific heat of aluminum is 0.90 J/(g × °C).)

 0.10 g

 10.0 g

 12.0 g

 57.7 g

sweetburger · Answer

$$q=mc \Delta T$$
q representing the amount of energy input into the aluminum
m representing the mass of the aluminum (you will isolating and solving for m)
c representing the specific heat of aluminium 
Delta T representing the change in temperature and can be rewritten like thi$$\Delta T= T_f-T_i$$