Ask your own question, for FREE!
Mathematics 24 Online
OpenStudy (jaylokss):

Someone check my answer?

OpenStudy (jaylokss):

OpenStudy (evoker):

First half is correct, but the second half you need to find the linear equation for the second part.

OpenStudy (jaylokss):

And how do you do that @Evoker

OpenStudy (evoker):

I would recommend perhaps using the point slope equation method if that sounds familiar to you.

OpenStudy (jaylokss):

Nah not really

OpenStudy (evoker):

y-y1=m(x-x1) where m is the slope and x1,y1 is a point on the line.

OpenStudy (jaylokss):

Oh okay

OpenStudy (mathstudent55):

Just look at the piece of the function that was graphed for the 2nd part. Notice three easy-to-read points: (3, 2), (4, 3), (5, 4) For each x-coordinate, the y-coordinate is one less than the x-coordinate. The suggests that the function for the second part is simply y = x - 1

OpenStudy (jaylokss):

So x-1 goes in the bottom one @mathstudent55

OpenStudy (mathstudent55):

Yes. \(y = 4, if~-1\le x \le 1\) \(y = x - 1, if~~3\le x \le 5\)

OpenStudy (jaylokss):

Ty

OpenStudy (mathstudent55):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!