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First half is correct, but the second half you need to find the linear equation for the second part.
And how do you do that @Evoker
I would recommend perhaps using the point slope equation method if that sounds familiar to you.
Nah not really
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y-y1=m(x-x1) where m is the slope and x1,y1 is a point on the line.
Oh okay
Just look at the piece of the function that was graphed for the 2nd part. Notice three easy-to-read points: (3, 2), (4, 3), (5, 4) For each x-coordinate, the y-coordinate is one less than the x-coordinate. The suggests that the function for the second part is simply y = x - 1
So x-1 goes in the bottom one @mathstudent55
Yes. \(y = 4, if~-1\le x \le 1\) \(y = x - 1, if~~3\le x \le 5\)
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Ty
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