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My answer: J(6, 3) M(-3, 4) d = √{[(6 - -3)^2] + [(3 - 4)^2]} d = √{[9^2] + [-1^2]} d = √{81 + 1} d = √82 d ≈ 9.06 K(-12, 5)
@TheSmartOne
I don't understand how you took the distance of of JM to find the coordinate K Granted that JM = MK since M is the midpoint mhmm
you are correct, but easier method is to use midpoint \[M = (\frac{x_1 +x_2}{2}, \frac{y_1+y_2}{2})\]
Yeah, you could plug in the (x1, y1) values you know and the midpoint values and solve for (x2, y2) so: \(\Large -3 = \frac{6+ x_2}{2}\) and \(\Large 4 = \frac{3 + y_2}{2}\)
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