Question

Check my answers?

Answer 1

For #4:
Part I: \[\frac{ -\sqrt3 }{ 2 }\] and \[\frac{ \sqrt3 }{ 2 }\]
Part II: pi/3, 2pi/3, 4pi/3, 5pi/3

Answer 2

I'm pluggin in \[\frac{ -\sqrt{3} }{ 2 },\frac{ \sqrt{3} }{ 2 }\] for x and not getting the equation equal to 0.

Answer 3

values that appear to be working for me are \[\frac{ - \pi }{ 3 },\frac{ \pi }{ 3 },and \frac{ 2\pi }{ 3 }\]

Answer 4

ignoring -pi/3 because it is outside of the domain. my mistake

Answer 5

hmm so pi/3 and 2pi/3 are working for part 1?

Answer 6

yes those values when plugged in for x set the equation to become 0=0

Answer 7

Wait - part 1 is just solving for sinx, part 2 are the actual solutions

Answer 8

OH woops

Answer 9

Lol :) it's okay

Answer 10

no wonder it seemed so off to me

Answer 11

Why would 4pi/3 and 5pi/3 not work?

Answer 12

creepy profile picture by the way. I just noticed it was you sweetburger! haha

Answer 13

I haven't tested those values yet they may. One moment.

Answer 14

and lol

Answer 15

5pi/3 works but 4pi/3 does not when you plug it in for x.

Answer 16

:/ I wonder why..

Answer 17

Solving for sinx, I should get \[\pm \frac{ \sqrt3 }{ 2 }\] right?

Answer 18

Hmm 4pi/3 actually would work.

Answer 19

Your work all looks correct to me Scrabble.
I dunno what spaghettiburger is going on about :O hmm

Answer 20

sin(4pi/3) equals -sqrt3/2...

Answer 21

lol

Answer 22

Hehehe xD

Answer 23

Okay, thanks :D Zep, do you know how to do #5? I'll open up a new Q, it's confuzzling me :/