Question

If f(x) = log3 (x + 1), what is f−1(2)?

Answer 1

@AloneS

Answer 2

The inverse will be what x gives you and answer of 2 in the original function

Answer 3

what?

Answer 4

Basically you want to set f(x)=2, that is the left side replace with 2 and then solve for x.

Answer 5

so 8?

Answer 6

so \[2=\log_{3}(x+1) \] which gives 3^2=x+1

Answer 7

yeah

Answer 8

can you help with more? I'm sorry these are so hard for me

Answer 9

sure i can help with a few more

Answer 10

thanks a lot

Answer 11

Ok, is that the f of g in your text, I assume so.

Answer 12

or no I guess it is multiply

Answer 13

ok, so you do need to use the log rules also, which i believe will give the second answer

Answer 14

That is for the second question I mean.

Answer 15

okay

Answer 16

For the third, same idea which appears to again give the second answer, remember the
\[a \log_{?} b=\log_{?} b^a\]

Answer 17

wait i only sent two questions i think

Answer 18

For the third, same idea which appears to again give the second answer, remember the
\[\log a + \log b = \log (a*b)\]

Answer 19

I meant the third in the thread

Answer 20

i just need this

Answer 21

and second in the thread

Answer 22

all the last 3 pics ive sent are the same question

Answer 23

okay sorry was confused, so what do i need to do ?

Answer 24

so first multiply by distributive
so 3x log - log

Answer 25

would it be b ?

Answer 26

now the first turns into
log x^3x by power rule
so you you have log x^3x - log x

Answer 27

Yeah

Answer 28

okay can you just check my answer on one last question?

Answer 29

Sure

Answer 30

is b correct

Answer 31

Actually I think c

Answer 32

okay darn

Answer 33

this simplifies to \[\log_{3}\frac{ 5(x-1) }{ (x-1) } \] what here cancels out?

Answer 34

perfect, and yes the x-1 cancels.

Answer 35

oops sorrry sweetburger, thought your were katecc379