Ask your own question, for FREE!
Mathematics 14 Online
OpenStudy (montsechamorro):

What is the value of y?

OpenStudy (montsechamorro):

OpenStudy (unklerhaukus):

is that a right angled isosceles triangle?

OpenStudy (montsechamorro):

it looks right angled but I thought it wasn't supposed to assume. But yes its an isosceles

OpenStudy (unklerhaukus):

it's in a circle, i think there is some theorem that says that angle-H has to a right angle

OpenStudy (shadowlegendx):

tbh, I believe we were all taught in Geometry class not to assume a triangle is 90 degrees, by looks, but I've come across problems where it's the only logical path...to assume that it's 90 degrees.

OpenStudy (shadowlegendx):

I think you're right @UnkleRhaukus

OpenStudy (montsechamorro):

so do i make it 3y+6=90

OpenStudy (shadowlegendx):

No, angle F is not 90 degrees

OpenStudy (unklerhaukus):

<F + <G + <H = 180 (triangle) <H = 90 (diameter triangle theorem) <F = <G (isosceles triangle )

OpenStudy (shadowlegendx):

There you have it ^

OpenStudy (shadowlegendx):

Just use that information to form an equation that solves for y

OpenStudy (unklerhaukus):

(diameter triangle theorem) = (Thales' theorem)

OpenStudy (montsechamorro):

I'm trying to figure out the equation but i don't understand.

OpenStudy (montsechamorro):

im so sorry its just really hard

OpenStudy (unklerhaukus):

substituting <F + <F + 90 = 180 simplify this then plug in <F = 3y+6

OpenStudy (montsechamorro):

2(3y+6)+90=180 ?

OpenStudy (unklerhaukus):

simplify the equation with <F, before substituting in 3y+6

OpenStudy (montsechamorro):

2f+90=180?

OpenStudy (unklerhaukus):

yeah, now keep simplifying ...

OpenStudy (unklerhaukus):

(take away 90) (divide by 2)

OpenStudy (montsechamorro):

so f=45

OpenStudy (unklerhaukus):

good, now f = 45 = 3y+6 solve for y

OpenStudy (montsechamorro):

so y=13?

OpenStudy (unklerhaukus):

\[\color{red}\checkmark \]

OpenStudy (montsechamorro):

thank you so much!! I cant express how grateful I am

OpenStudy (montsechamorro):

Could you help me with another problem or do i have to make a new question

OpenStudy (unklerhaukus):

Welcome to OpenStudy! I would probably be easiest to close this question, and open a new one, i'll see you there!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!