What is the value of y?
is that a right angled isosceles triangle?
it looks right angled but I thought it wasn't supposed to assume. But yes its an isosceles
it's in a circle, i think there is some theorem that says that angle-H has to a right angle
tbh, I believe we were all taught in Geometry class not to assume a triangle is 90 degrees, by looks, but I've come across problems where it's the only logical path...to assume that it's 90 degrees.
I think you're right @UnkleRhaukus
so do i make it 3y+6=90
No, angle F is not 90 degrees
<F + <G + <H = 180 (triangle) <H = 90 (diameter triangle theorem) <F = <G (isosceles triangle )
There you have it ^
Just use that information to form an equation that solves for y
(diameter triangle theorem) = (Thales' theorem)
I'm trying to figure out the equation but i don't understand.
im so sorry its just really hard
substituting <F + <F + 90 = 180 simplify this then plug in <F = 3y+6
2(3y+6)+90=180 ?
simplify the equation with <F, before substituting in 3y+6
2f+90=180?
yeah, now keep simplifying ...
(take away 90) (divide by 2)
so f=45
good, now f = 45 = 3y+6 solve for y
so y=13?
\[\color{red}\checkmark \]
thank you so much!! I cant express how grateful I am
Could you help me with another problem or do i have to make a new question
Welcome to OpenStudy! I would probably be easiest to close this question, and open a new one, i'll see you there!
Join our real-time social learning platform and learn together with your friends!