So, part one of 2. Do I combine like terms? http://prntscr.com/bz0ogg
@TheSmartOne
No, you plug in x = -3 in to the equation and solve for y Then you plug in y = -4 in to the equation and solve for x :)
So, in this case. 6x+7y=4x+4y Input x (-3) -18 + 7y = -12 + 4y Input y (-4) -18 - 28 = -12 - 16 This statement is not true.
Oh, no, not like that :P First part of the question, you plug in x = -3 -18 + 7y = -12 + 4y Now you solve for y Each point is an (x, y) x is the input, y is the output value you plug in x to get a y occasionally they make you plug in y to get x to make sure you understand that as long as you have one value, you can find the other to do the next part of the question, you plug in y = -4 6x + 7(-4)=4x + 4(-4) And you solve for x :)
Do I add -12 on both sides?
-18 + 7y = -12 + 4y Yes, add 12 on both sides, and then subtract 7y on both sides. And then divide by whatever coefficient there is with y on both sides to isolate y :)
-18+7y = -12+4y +12 +12 -6+7y = 4y -7y -7y -6 = -3y
Is that it?
@TheSmartOne
now solve for y :)
y = 2
Is it right?
yes, now that's the answer for one part of it now we need to do the second half of the question and find the x-value for when y = -4 6x + 7(-4)=4x + 4(-4) solve for x :)
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