A body is thrown up with a velocity of 29.23ms^-1 distance travelled in the last second of upward motion is?
Assuming the body will fall and terminal velocity is not reached, find out the distance it will travel up by using v² = u²+2as where v² is 0 and a is -9.81 Then use the the same distance again in the same equation to find the ending velocity v v² = u²+2as where u² is 0 and a is 9.81 Note :- Dont mess up the signs of acceleration
I got 41.28...
If you're talking about ending velocity then incorrect, if you're talking about displacement you're close to correct answer
I got S to be 43.49 m ...but thats not an option...
S is correct. But you have to find out v
i got v 29.19ms^-1
It should be 29.23 exactly the same as initial velocity. Can you figure out why? (Hint. Consider energies)
No loss of energy?
Okay yes but can you figure out a relation of absence of loss has to do with equality of u=v?
How do I do so?
Okay so when the ball rises, the kinetic energy converts to gravitational potential energy right? And because no resistances are mentioned, kinetic energy is converted completely to GPE. Agree?
Yes.
So after stopping in the air, the GPE starts to get converted to KE. When the distance risen matched distance fallen, the GPE is converted completely to KE. Agree?
Okay?
So we can conclude that KE at start = Gain in GPE = KE at end KE at start = KE at end V at start² x 0.5 x m = V at end² x 0.5 x m V at start²= V at end² V at start= V at end I hope you aren't confused.
ya okay...what next?
This is the proof that Velocity will remain same if the distance fallen = distance risen
However, since the question is ambiguous the upper answer was for if the ball starts to fall back But what about if they are asking the final velocity of the ball assuming the ball doesn't fall back? Simple. Because the acceleration is in opposite direction to velocity, the smallest value the velocity can reach is 0 and thus the final velocity will be 0. I hope this clears up your confusions
They have asked the displacement ....
That's the trick. I am sorry I didn't explain it before. Distance traveled in a second = Velocity. Distance traveled in the last second = Ending Velocity
.... 29.23 is not an option....
Can you show us the options
2.3 6 9.8 4.9
Are you sure the wordings of the question is correct?
yes,yes i am...
Well the question is incorrect. Reasons. 1:- They haven't defined the time limit from which we can conclude what exactly is the last second 2:- They haven't defined the displacement that will occur( displacement till v= 0) isn't a valid assumption here since the choices doesn't contain 0 as an option
If you had provided the choices beforehand, I would've given the same conclusion earlier. Apologies for wasting your time
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