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Mathematics 15 Online
OpenStudy (faiqraees):

What properties do prime numbers exhibit which can be used in proofs to define them? Like rational numbers have a unique property that they can be expressed as a quotient of a/b. Even numbers have a unique property of divisibility by 2 and thus they can be expressed as 2x. Similarly are there any unique properties for prime numbers?

OpenStudy (faiqraees):

@ganeshie8

OpenStudy (evoker):

I guess you could say if two integers multiply together to equal it one has to be one and the other has to be the number, or to put it another way if a*b=c and both a and b are integers that aren't 1 then c is not a prime.

OpenStudy (faiqraees):

Like if there is a question "Prove that a prime number......" For this I have to assume there is a prime number x How should I define this x in mathematical terms ?

OpenStudy (evoker):

To be honest that is about it, I don't suppose you have a specific proof in mind.

OpenStudy (faiqraees):

Prove that there prime numbers beyond 3 are of the form 6x+1 or 6x-1

OpenStudy (evoker):

That is true you could say it is not divisible by anything but one and itself

OpenStudy (faiqraees):

How could I say that X is a prime number such that X =1*X I can't use the same thing in its definition Its like saying "Prime number is a number such that it is prime"

OpenStudy (evoker):

you could say x is a prime number such that x/y is not an integer when y is not 1 or x.

OpenStudy (faiqraees):

I cant use x in the definition that's the problem. Its like saying X is a prime number such that a PRIME divided by !(1 or itself) is an integer The contradiction is what is the PRIME?

OpenStudy (faiqraees):

@Loser66 I dont need the solution to that proof. I want a way to define a prime number

OpenStudy (loser66):

I think only one way is to find its factor

OpenStudy (faiqraees):

@ganeshie8

ganeshie8 (ganeshie8):

Hey!

OpenStudy (faiqraees):

Hey

ganeshie8 (ganeshie8):

Stick to the definition of a prime. By definition, a prime number is an integer whose positive factors are 1 and itself.

ganeshie8 (ganeshie8):

So, in order to prove a number is prime, you just have to prove that the only positive factors of it are 1 and itself.

OpenStudy (faiqraees):

And how can I do that?

ganeshie8 (ganeshie8):

Consider the example : Prove 7 is a prime

ganeshie8 (ganeshie8):

7 is not divisible by 2, 3, 4, 5, 6

ganeshie8 (ganeshie8):

therefore it is a prime. end of story.

OpenStudy (faiqraees):

Prove that 6x+1 is prime if 6x+1>3. How should I use your way here

ganeshie8 (ganeshie8):

That statement is wrong

ganeshie8 (ganeshie8):

6*4 + 1 = 25 is not a prime

OpenStudy (faiqraees):

Oh sorry 6x+1 or 6x-1

ganeshie8 (ganeshie8):

That should also be wrong.

ganeshie8 (ganeshie8):

Can you put the full statement in one reply ?

OpenStudy (faiqraees):

Prove that there prime numbers beyond 3 are of the form 6x+1 or 6x-1

ganeshie8 (ganeshie8):

That looks good. Do you see yet why I say your earlier statements are wrong ?

OpenStudy (faiqraees):

Yes, the implying relations were wrong. Here the converse of this statement is not true

ganeshie8 (ganeshie8):

Every prime number beyond 3 is of form 6x + 1 or 6x - 1 is not same as saying Every number of form 6x + 1 or 6x - 1 is a prime

ganeshie8 (ganeshie8):

Good.

ganeshie8 (ganeshie8):

Let me ask you a question

ganeshie8 (ganeshie8):

When you divide a number by 6, what are the remainders you expect ?

OpenStudy (faiqraees):

smaller than 6

ganeshie8 (ganeshie8):

What exactly are they ? Can you list them here ?

OpenStudy (faiqraees):

1,2,3,4,5

ganeshie8 (ganeshie8):

You missed 0

OpenStudy (faiqraees):

Oh yes

OpenStudy (faiqraees):

0,1,2,3,4,5

ganeshie8 (ganeshie8):

Would you agree that ANY integer can be expressed as 6x + k, where x is some integer and 0 <= k < 6 ?

OpenStudy (faiqraees):

Obviously

ganeshie8 (ganeshie8):

Sure ?

OpenStudy (faiqraees):

yes

ganeshie8 (ganeshie8):

What are x and k for 25 ?

OpenStudy (faiqraees):

x=4 k=1

ganeshie8 (ganeshie8):

Yes. How about 30

OpenStudy (faiqraees):

x=5 k=0

OpenStudy (faiqraees):

oh got it done.

ganeshie8 (ganeshie8):

Good. So we can express every integer in the form 6x + k, where x is some integer and k is between 0 and 6

OpenStudy (faiqraees):

k cant be 2,3,4 but it can be 1 or5 which is in other words 6-1 thus the only established values for k are 1 and -1 for a prime

ganeshie8 (ganeshie8):

why can't k be 2,3,4 ?

OpenStudy (faiqraees):

well multiple of 6x + 2 divisible by 2 6x+3 divisble by 3 6x+4 divisble by 2

ganeshie8 (ganeshie8):

You got it!

OpenStudy (faiqraees):

But I am stuck at my question. How should I define a prime If say I assume that X is a prime such that .....(what should I write here)?

ganeshie8 (ganeshie8):

As I said, stick to the definition. There is no known form for a prime. They are strange and hard.

ganeshie8 (ganeshie8):

If you assume x is a prime, then the definition says that the only factors of x are 1 and x.

OpenStudy (faiqraees):

Can't I just use the 6x+1 or 6x-1 definition?

ganeshie8 (ganeshie8):

You may use it. Just be cautious that not all integers of form 6x + 1 or 6x-1 are primes.

ganeshie8 (ganeshie8):

As you said, the converse of a statement need not follow the truth value of the actual statement. All horses have four legs doesn't imply All four legged animals are horses

OpenStudy (faiqraees):

Okay one more Prove by contradiction that if x<25 and y<25 then x+y>50 is false

OpenStudy (faiqraees):

I know the basic idea. But How should I express it

ganeshie8 (ganeshie8):

Any contradiction proof starts by assuming the opposite of what needs to be proven.

ganeshie8 (ganeshie8):

So start by assuming the opposite of whatever you want to prove.

OpenStudy (faiqraees):

x+y >50 is true

ganeshie8 (ganeshie8):

Yes

OpenStudy (faiqraees):

x<25 y<25 x+y<25+25 x+y<50 Right???

ganeshie8 (ganeshie8):

That looks okay, but where's the contradiction ?

OpenStudy (faiqraees):

x+y<50 since we assume x+y>50 is true. But my main question is it okay to add or subtract inequalities like that. Are there some laws that govern their manipulation?

ganeshie8 (ganeshie8):

It is perfectly okay if it makes sense to you.

ganeshie8 (ganeshie8):

x < 25 y < 25 do imply x + y < 25 + 25 I don't see anything wrong here. Do you ?

ganeshie8 (ganeshie8):

Two sticks that are less then 25 cannot add up to a length more than 25+25.

ganeshie8 (ganeshie8):

Easy to see right ?

OpenStudy (faiqraees):

yes, but what if I am squaring or applying a function on them or multiplying by something like x^2 * y^2 <2500*2500. That would be correct right?

ganeshie8 (ganeshie8):

Looks good to me. But keep in mind, each case is different. There is no one single trick that works in all cases. If you followed the rules of math correctly while manipulation, you would be fien.

OpenStudy (faiqraees):

Oh okay, one thing. Are you always online at this time?

ganeshie8 (ganeshie8):

Mostly yes. If not, you may tag me in your question and I'll respond when I login. I like your questions :)

OpenStudy (faiqraees):

See it gets a little burden for me be online for the whole day to get help from you hoping that you would come online at one moment or other Thanks

ganeshie8 (ganeshie8):

inequalities become a bit tricky when you allow negative numbers x < a need not imply x^2 < a^2

OpenStudy (faiqraees):

Yeah I learnt that. We have to account for their increasing and decreasing properties

ganeshie8 (ganeshie8):

-5 < 1 is true but (-5)^2 < 1^2 isn't

ganeshie8 (ganeshie8):

So you must use your reason when manipulating these. Simply squaring both sides doesn't work. You may add or subtract stuff both sides though.

OpenStudy (faiqraees):

Okay one more thing in proof in which I have to deal with digits of integers how should I do them? Like prove that number whose digits add up to 3x is divisible by 3 (I made this question so it isn't necessary for it to be true.)

ganeshie8 (ganeshie8):

let me ask you a question

ganeshie8 (ganeshie8):

what does the number 435 represent ?

OpenStudy (faiqraees):

4 hundreds 3 tens 5 ones ?

ganeshie8 (ganeshie8):

Exactly! 435 is a shortcut form for the decimal expansion : 4*10^2 + 3*10^1 + 5*10^0

ganeshie8 (ganeshie8):

4*10^2 + 3*10^1 + 5*10^0 looks lengthy and ugly so we express it in compact form as 435

ganeshie8 (ganeshie8):

Now look at the powers of 10

OpenStudy (faiqraees):

Okay

ganeshie8 (ganeshie8):

What is the remainder when 10 is divided by 3 ?

OpenStudy (faiqraees):

1

ganeshie8 (ganeshie8):

What is the remainder when 10^2 is divided by 3 ?

OpenStudy (faiqraees):

it will remain 1 if n>0

ganeshie8 (ganeshie8):

Good. So any power of 10 leaves the remainder 1 when divided by 3

ganeshie8 (ganeshie8):

Look at our number 435 : 4*10^2 + 3*10^1 + 5*10^0

ganeshie8 (ganeshie8):

As far as remainders when divided by 3 are concerned, can we say the number is equivalent to : 4*1^2 + 3*1^1 + 5*1^0 ?

ganeshie8 (ganeshie8):

That is same as 4 + 3 + 5

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