Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (mabby00):

* Algebra 2! * Quick Question. Can someone explain how to simplify 10√x^11

OpenStudy (evoker):

ah well x^11 is the same as x^5*x^5*x so as you can see there are a pair of x^5 in the root, what do you think at that point.

OpenStudy (mabby00):

I'm not sure. Still confused. The original equation I had was \[10\sqrt{x^5 * x^4 * x^2}\]

OpenStudy (evoker):

you wer correct to do what you did initially and put them together, but keep in mind simplifying a normal square root such square root of 12, how would you do that?

OpenStudy (mabby00):

I would find the common factor/ number that goes into it evenly.

OpenStudy (evoker):

yes basically like 2 for that case

OpenStudy (mabby00):

Ok.

OpenStudy (evoker):

so for x^11, x^5 goes in evenly

OpenStudy (mabby00):

OH

OpenStudy (mabby00):

So then, what would you do with the 5x?

OpenStudy (mabby00):

sorry

OpenStudy (mabby00):

x^5

OpenStudy (evoker):

So with square root of 12 where 12 = 2*2*3 you would get 2 times the square root of 3 right

OpenStudy (evoker):

so apply the same logic

OpenStudy (evoker):

what happens to the 2 in square root of 12 will happen to the x^5 and what happens to the 3 will happen to the left over x

OpenStudy (mabby00):

Is there a way you could draw this out?

OpenStudy (evoker):

|dw:1469804484863:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!