* Algebra 2! * Quick Question.
Can someone explain how to simplify 10√x^11
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OpenStudy (evoker):
ah well x^11 is the same as x^5*x^5*x so as you can see there are a pair of x^5 in the root, what do you think at that point.
OpenStudy (mabby00):
I'm not sure. Still confused. The original equation I had was \[10\sqrt{x^5 * x^4 * x^2}\]
OpenStudy (evoker):
you wer correct to do what you did initially and put them together, but keep in mind simplifying a normal square root such square root of 12, how would you do that?
OpenStudy (mabby00):
I would find the common factor/ number that goes into it evenly.
OpenStudy (evoker):
yes basically like 2 for that case
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OpenStudy (mabby00):
Ok.
OpenStudy (evoker):
so for x^11, x^5 goes in evenly
OpenStudy (mabby00):
OH
OpenStudy (mabby00):
So then, what would you do with the 5x?
OpenStudy (mabby00):
sorry
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OpenStudy (mabby00):
x^5
OpenStudy (evoker):
So with square root of 12 where 12 = 2*2*3 you would get 2 times the square root of 3 right
OpenStudy (evoker):
so apply the same logic
OpenStudy (evoker):
what happens to the 2 in square root of 12 will happen to the x^5 and what happens to the 3 will happen to the left over x
OpenStudy (mabby00):
Is there a way you could draw this out?
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