Question

PLEASE HELP NOW.

Answer 1

@ILovePuppiesLol @imqwerty @sweetburger

Answer 2

@.Sam.

Answer 3

@zpupster

Answer 4

@legomyego180

Answer 5

@undeadknight26

Answer 6

Ray and Kelsey are working to graph a third-degree polynomial function that represents the first pattern in the coaster plan. Ray says the third-degree polynomial has 4 intercepts. Kelsey argues the function can have as many as 3 zeros only. Is there a way for the both of them to be correct? Explain your answer.

Answer 7

@CamPayne please help :)

Answer 8

Of course there is no way for them to be both correct, since they contradict each other.

Here is how to prove Ray incorrect. Suppose that a polynomial has four roots: s, t, u, and v. If the polynomial were evaluated at any of these values, it would have to be zero. Therefore, the polynomial can be written in this form.

p(x)(x - s)(x - t)(x - u)(x - v), where p(x) is some non-zero polynomial

This polynomial has a degree of at least 4. It therefore cannot be cubic.

Now prove Kelsey correct. We have already proved that there can be no more than three roots. To prove that a cubic polynomial with three roots is possible, all we have to do is offer a single example of that. This one will do.

(x - 1)(x - 2)(x - 3)

This is a cubic polynomial with three roots, and four or more roots are not possible for a cubic polynomial. Kelsey is correct.

Incidentally, if this is a roller coaster we are discussing, then a cubic polynomial is not such a good idea, either for a vertical curve or a horizontal curve.

Answer 9

cheater lol