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Mathematics 16 Online
OpenStudy (aaronrocky):

Dilation mistake, I can't seem to find it... So my problem is I need to find point B. My givens of the original polygon are: F(-6,-1) G(-1,-1) H(-2,-4) I(-7,-4) My givens of the dilated polygon are: A(3,8) D(1,2)

OpenStudy (aaronrocky):

So far I have done the distance formula for AD and got 2sqrt(10) or 6.32 and FI and got sqrt(10) or 3.16 Then I did 2sqrt(10) / sqrt(10) = 2 With me having 2, where do I go from there? Multiply G by 2, to find B?

OpenStudy (aaronrocky):

Or, do I have to find the distance of BC by dilating GH?

OpenStudy (welshfella):

how did you get 3.16? the distance from f1 to which point?

OpenStudy (aaronrocky):

F to I

OpenStudy (aaronrocky):

https://gyazo.com/213cdb5601f71fd004ae25df1ba09e4c Theres a picture

OpenStudy (welshfella):

yes thats the correct correspond line in the polygons

OpenStudy (welshfella):

AB equals the length of FG * 2

OpenStudy (aaronrocky):

Okay so once I divided 2sqrt(10) / sqrt(10) and got 2, I multiplied 2 by 3 because of FI and got 6, so now do I just add 6 to A's X cord?

OpenStudy (welshfella):

so just work out length of FG.

OpenStudy (aaronrocky):

Oh haha I was thinking that I had to add 6 to A's X

OpenStudy (aaronrocky):

Okay so I got 10 for FG*2

OpenStudy (welshfella):

the y coordinates are the same for points F and G so length of FG = -1-(-6)

OpenStudy (aaronrocky):

so 5*2 = 10

OpenStudy (aaronrocky):

So B should rest on (10,8) ?

OpenStudy (welshfella):

yea AB = 10

OpenStudy (aaronrocky):

I mean 13,8

OpenStudy (welshfella):

yes

OpenStudy (welshfella):

(13,8)

OpenStudy (aaronrocky):

Okay, thank you :)

OpenStudy (welshfella):

yw

OpenStudy (welshfella):

theres no need to use the pythagoras formula for the length of the line if its horizontal or vertica.

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