Let f(x)equals=x^2+4x and g(x)equals=1−x. Find f(2)minus−g(2).

f(2)minus−g(2)equals=___ (Simplify your answer.)

Question

Let f​(x​)equals=x^2+4x and g​(x​)equals=1−x. Find ​f(2)minus−​g(2​).

​f(2​)minus−​g(2​)equals=___ ​(Simplify your​ answer.)

shortypants · Answer

would this be 2x^2+4(2)-1-(2)

shortypants · Answer

i mean (2^2)+4(2)-1-(2)

shortypants · Answer

if so is the answer 9

mathstudent55 · Answer

"=" means "equals"
"-" means "minus"
There is no need to write =equals or -minus which just confuses.

shortypants · Answer

sorry that was just a copy paste error from the program im using

brydenwright · Answer

If you put 2 into f(x), you get 12, or 4+8. When you plug in 2 into g(x), you get 1-2, or -1. 12--1 is the same as 12+1, so the answer would be 13.

shortypants · Answer

oh i see you solved both sides on there own before subtracting them?

brydenwright · Answer

Yeah, because it's really (x^2+4x)-(1-x)

shortypants · Answer

ok thank you.

mathstudent55 · Answer

$f​(x​)=x^2+4x$   and   $g​(x​)=1−x$

There are different ways of finding your answer.
Here is one way.
First, find an expression for f(x) - g(x).
Then let x = 2 and evaluate.

 $f​(x​) - g(x) =x^2+4x - (1−x)$

 $f​(x​) - g(x) =x^2+4x - 1 + x$

$f​(x​) - g(x) =x^2+5x - 1)$

$f​(2​) - g(2) =2^2+5(2) - 1 = 4 + 10 - 1 = 13$

Here is another way.
First evaluate f(2) and g(2) then do the subtraction.

 $f​(x​)=x^2+4x$

 $f​(2​)=2^2+4(2) =4 + 8 = 12$

$g​(x​)=1−x$

$g​(2​)=1−2 = -1$

$f(2) - g(2) = 12 - (-1) = 12 + 1 = 13$