Rearrange the titration calculation to find Mb in a solution. If I put 13.2 mL of NaOH and 0.3 mL of phenolphthalein in 25 mL of KHP, what is the Mb of the solution? The original solution of NaOh is 100 mL and is composed of 1.069e-15 moles of H+, 9.445e-2 moles of OH-, and 9.445e-2 moles of Na+. The KHP is 25 mL and is composed of 4.433e-5 moles of H+, 1.424e-13 moles of OH-, 1.246e-2 moles of KHP, and 4.433e-5 moles of KHP-.
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what is Mb?
@cuanchi Mb is molarity of the basic solution.
1) I assume you want to calculate the molarity of the mix "13.2 mL of NaOH and 0.3 mL of phenolphthalein in 25 mL of KHP" 2) you have to calculate how many moles of NaOH and How many moles of KHP you have in the mix. 3) then subtract the smaller from the bigger and that will tell you how many moles of base or acid you have in excess. 4) Then add the two volumes 25+13.5=38.5mL = 0.035 L that is the volume of your mix 5) calculate the Molarity = moles/ volume (L) with the moles from 3 and the volume from 4.
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