Question

Can someone help me with this please.

Answer 1

What's the problem?

Answer 2

\[\frac{ 1 }{ x+y} =12 \]\[\frac{ 3x }{ y }=-4\]

Solve the system of equations by addition method, if possible.

Answer 3

@Idealist10 there it is

Answer 4

Okay, so if \[\frac{ 1 }{ x+y }=12\] and \[\frac{ 3x }{ y }=-4\], then \[3x=-4y\], right?

Answer 5

mhmm

Answer 6

\[x+y=\frac{ 1 }{ 12 }\]
\[x=-\frac{ 4 }{ 3 }y\]
Substitute x, you get
\[-\frac{ 4 }{ 3 }y+y=\frac{ 1 }{ 12 }\]
that gets you
\[-\frac{ 1 }{ 3 }y=\frac{ 1 }{ 12 }\]
now you can solve for y, which is
\[y=-\frac{ 1 }{ 4 }\]
and \[x=\frac{ 1 }{ 3 }\].

Answer 7

I get it now, Thank you @Idealist10 ! :)

Answer 8

You're welcome! I'm glad that you got it now.