Question

Solve Sqrt(4y+5)-Sqrt(y-1)=3

Answer 1

Please tell me if I'm headed in the right direction and guide me please!

Answer 2

Sqrt(4y+5)-Sqrt(y-1)=3
Sqrt(4y+5)=3+Sqrt(y-1)
4y+5=9+6Sqrt(y-1)+y-1

Answer 3

4y+5=8+6Sqrt(y-1)+y
3y+5=8+6Sqrt(y-1)
3y-3=6Sqrt(y-1)

Answer 4

1/2y-1/2=Sqrt(y-1)
1/4y^2-2/4y-1/4=y-1
y^2-2y-1=y-1

Answer 5

y^2-2y=y
y^2-3y=0
y(y-3)=0
y={0,3} but that's not correct, it's {1,5}

Answer 6

you should get

\(\Large\frac{1}{4}y^2 - \frac{1}{2}y \color{red}{+}\frac{1}{4}=y-1\)

Answer 7

(a - b)^2 = a^2 - 2ab + b^2

it should be a plus, not a minus

also I just went ahead and simplified 2/4y to 1/2y

Answer 8

I would have but I thought I would multiply by 4 to get rid of the fractions. And thanks I didn't catch that mistake.

Answer 9

So revised:
1/4y^2-2/4y+1/4
y^2-2y+1=y-1
y^2-2y+2=y

Answer 10

y^2-3y+2=0
(y-1)(y-2)=0
y={1,2} still not {1,5} so I'm still wrong somewhere.

Answer 11

If a = b

then ac = bc

you multiplied 4 on the left side, you have to do so at the right side also

Answer 12

Oh....

Answer 13

Thank you so much!!!! Now off to reattempt that test!!!! THANK YOU!

Answer 14

YESSS I GOT IT RIGHT THANK YOU SOOOOO MUCH YOU HAVE NO IDEA HOW MUCH I ALMOST CRIED OVER THIS ONE