Question

Limit questions...

Answer 1

I'm on 25 and 26...
For 25, I tried multiplying by the conjugate of the numerator, but i ended up with the same equation just with t in the numerator and a sign change in the denominator. It's still giving me an indeterminate form.

Answer 2

I think I figured 26 out, but I'm still stuck on 25

Answer 3

\[\large \frac{ (\sqrt{1+t} -\sqrt{1-t} )}{ t }*\frac{ (\sqrt{1+t} +\sqrt{1-t}) }{( \sqrt{1+t} +\sqrt{1-t} ) }\]notice diff. of two squares on top\[\large \frac{ \sqrt{1+t}^2 -\sqrt{1-t}^2 }{ t(\sqrt{1+t} +\sqrt{1-t}) }\] \[\large \frac{ 1+t -(1-t) }{ t(\sqrt{1+t} +\sqrt{1-t}) } \]
\[\lim_{t \rightarrow 0}\large \frac{ 2t }{ t(\sqrt{1+t} +\sqrt{1-t}) }=? \]

Answer 4

0 right? which is indeterminate?

Answer 5

I left the last step for you to simplify

Answer 6

Look closely\[\Huge \lim_{t \rightarrow 0} \frac{ 2t }{ t(\sqrt{1+t} +\sqrt{1-t}) }=?\]

Answer 7

Sup dude @johnweldon1993

Answer 8

Haha how ya doin man....I like how you said "look closely" and wrote it in a bigger font lol

But yeah...right off the bat @Abbles do you see anything that can be canceled?

Answer 9

Long time no see. I made it as big as possible haha, i think there are larger fonts but idk how to do them.

Answer 10

The t, right.. but then wouldn't it still be 0?

Answer 11

Not quite, "on my phone so latex would be incredibly annoying"

But take out the "t" on top and bottom and plug in 0 for the remaining t's and simply...what do you get?

Answer 12

\[\Huge \lim_{t \rightarrow 0} \frac{ 2 }{ \sqrt{1+t} +\sqrt{1-t}}=\]
\[\Huge \frac{ 2 }{ \sqrt{1+0} +\sqrt{1-0}}=\]

Answer 13

\[\Huge \frac{ 2 }{ \sqrt{1} +\sqrt{1}}=\]

Answer 14

And yeah @agent0smith I'm never on because I got 2 jobs this summer...don't have all the time anymore

Should be better when I head back to uni for the term...senior year!!!

Answer 15

Ah, that's no fun. Senior year should be more fun.

\[\Huge \frac{ 2 }{ 1 +1}= \]

Answer 16

\[\Huge \frac{ 2 }{ 2}=\]

Answer 17

Lmao I think they got it XD but doesn't get more simplified than that!

Answer 18

haha yeah Abbles is a smart girl. But she has a sense of humour too. Divide top and bottom by a common factor

\[\Huge \frac{ 2 \div2 }{ 2\div2}= \]

Answer 19

Ayyy I dunno what I was doing! Okay, that makes a lot of sense. Thank you so much!

Answer 20

She'll probably have a laugh while eating some oreos \[\Huge \frac{ 1 }{ 1 }= \]

Answer 21

Yeah yeah :)

Answer 22

Thanks Agent

Answer 23

Oreos smh. More like spinach and carrots.

Answer 24

\[\Huge \frac{ 1 }{ 1 }= 1 \div 1\]now lets do long division to finish this bad boy off

Answer 25

Now let's ask myself why I'm doing long-division at 4:36 am.

Answer 26

Wait now I'm confused. What next?

Answer 27

You still have to box your answer so the teacher knows.