Quadrilateral OPQR is inscribed inside a circle as shown below. What is the measure of angle P? You must show all work and calc ulations to receive credit.
http://learn.flvs.net/webdav/assessment_images/educator_geometry_v16/09_08_12.gif
I can't access your link. Can you draw it or take a pic of your problem and post it?
I tried attaching a picture but I couldn't post it.
Nevermind.
@mathstudent55
@triciaal
some useful info sum of the angles in a quadrilateral is 360 degrees N is the center of the circle so ON = RN etc for all the points that form the radii
Okay.
So, I still don't understand how I would solve for P.
I know the Inscribed Quadrilateral Theorem The opposite angles of an inscribed quadrilateral to a circle are supplementary.
Which means their sum is 180degrees
But I don't know how to find out P using this information..
In an inscribed quadrilateral, opposite angles are supplementary.
That will give you and equation for x and an equation for y. Then you can solve both equations separately to find x and y.
Since the problem only asks for angle P, then use angle P and the opposite angle to P, angle R. Add their measures and set the sum equal to 180 since angles P and R are supplementary. Than solve for y. Since angle P measures y, the value you get for y is your answer.
I am still a bit confused so would I combine angle P and angle R into an equation to get Y? Like (3y+8) y = 180 degrees? I feel like I am not properly understanding this.
And would my answer be 43?
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