Double angle identity help
Prove whether this is an identity: cos^2(2x) - sin^2(2x) = 0 To use the double angle identity on this, would I put it to the fourth power?
First of all it's not an identity, it's an equation
cos^2(2x) - sin^2(2x) = cos(4x)=0
I'm supposed to prove whether it's an identity or not... at least, that's what the instructions say
How does it equal cos(4x)? thanks Faiq :)
If that's the case, reduce to cos(4x) and then state that cos(4x)≠0 for all real values of x =cos²(2x)-sin²(2x) =cos²(y)-sin²(y) y=2x cos(2y)=cos²(y)-sin²(y) =cos(2y) =cos(2(2x)) y=2x =cos(4x)
Give it a counter example to show that it is not an identity, then you are good. Let say, if x = pi/2, then 2x = pi, right? cos (pi) = -1 and sin (pit) =0 then you have cos^2 (pi) + sin^2(pi) = 1 \(\neq \) 0 therefore, it is not an identity.
Thank you both!
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