Question

if Mary pitches a a baseball with the initial height of 6 feet and a velocity of 73 feet per sec, how long will it take for the ball to hit the ground

Answer 1

For this we use the second integral equation of acceleration (position equation)

\[-4.9t^2 +v_0t + s_0\] Where t is the time it takes, v_0 is the initial velocity and s_0 is the inital position.

Answer 2

so the answer is 0 sec

Answer 3

At 0 seconds, the ball has just left the hand at 6 feet. Plug in the known values and use the quadratic formula to solve for time.

Answer 4

-4.9t2+73t but i cant figure out the rest

Answer 5

s_0 is the initial position, which is the initial height off of the ground, 6.

Answer 6

so -4.9t2+73t+6

Answer 7

That's right, now just use the quadratic formula to solve for t.

Answer 8

is it -9.8

Answer 9

Not quite. The quadratic formula is this:\[t = \frac{ -b \pm \sqrt(b^2 - 4ac) }{ 2a}\] where b is the coefficient of the x term, a is the coefficient of the x^2 term, and c is the numerical term

Answer 10

-4.9x^2+79

Answer 11

but that is not a closed answer

Answer 12

but is that it

Answer 13

Doing the quadratic equation can get messy. I recommend using this: https://www.mathsisfun.com/quadratic-equation-solver.html

Answer 14

that told me 14.97

Answer 15

Yes, it plugs in the A, B and C values into the quadratic equation. That means it takes 14.97 seconds for the ball to hit the ground.